Recent content by Sajjad

The charge flowing through a circuit is q(t)=[3e^(-t) - 5e^(-2t)]--------(1) find the value of t and then current i. as i=dq/dt. i am doing it like this i=-3e^-t + 10e^-2t.....taking derivative let e^-t=u...for eaze i=10[u^2-3u/10] let 1=0 then 10[u^2-3u/10]=0 10[u^2...

The charge flowing through a circuit is q(t)=[3e^(-t) - 5e^(-2t)]--------(1) find the value of t and then current i. as i=dq/dt. i am doing it like this i=-3e^-t + 10e^-2t.....taking derivative let e^-t=u...for eaze i=10[u^2-3u/10] let 1=0 then 10[u^2-3u/10]=0 10[u^2...

i think! everyone knows that i= q/t in general but to find current i at some instant we have i= di/dt. In the given equation above if we can find the value of t we can put this value of t back in the equation and can find the charge q. by having charge q and time t, current i can be found by...

Book Try this book "Physic for scientist and Engineers" by Raymond A. Serway, Robert Beichner. it will definitely help you out.

The charge flowing through a circuit is q(t)=[3e^(-t) - 5e^(-2t)]--------(1) find the value of t and then current i. as i=dq/dt. i am doing it like this i=-3e^-t + 10e^-2t.....taking derivative let e^-t=u...for eaze i=10[u^2-3u/10] let 1=0 then 10[u^2-3u/10]=0 10[u^2...