Recent content by shadow5449

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    Area problem

    How would I go about checking for definate integrals? The book we use is not very descriptive on this topic. Thanks.
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    Working problem 3 ways

    I have to work this problem 3 ways, and I've gotten two, but am not sure about the third way. integral (x/sqrt(x^2-9))dx the first way I worked by setting u = x^2 - 9 the second way I worked by setting x = 3sec(theta) but the third way I have no clue, the book gave us a hint: Let x^2 - 9 =...
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    Integral problem

    I've almost gotten through this one integral problem, but i've seem to have gotten stuck: integral ((sqrt(4-x^2))/x) dx i let x = 2sin(theta), and dx = 2cos(theta)d(theta) sqrt(4-x^2) = 2cos(theta) integral ((2cos(theta))/(2sin(theta)) * 2cosd(theta) 2 integral...
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    Area problem

    This one has me stumped, I dont even know where to start. -Find the area of the triangular region in the first quadrant that is bounded above by the curve y=e^(2x), below by y=e^x, and on the right by the line x=ln(3). Thanks for any help
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    Help with problem

    A = L(h) A = L(16 - L²) A = 16L - L³ A` = 16 – 3L² 16 – 3L² = 0 √(L²) = √(16/3) L = 2.3094011 h = (16 – 2.3094011²) h = 10.6666 A = 24.63361146 Then I times it by 2 to account for the other side of the parabola (right?) A = 49.26722297
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    Help with problem

    Well, I know that the f(x) is going to be an upside down parabola. The area of a rectangle is obviously A = l(w). You would have to find the points on the graph to have your top line...but I'm not sure how you would do this. I'm thinking somthing with the derivative but that's where I'm stuck.
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    Help with problem

    Can anyone help me with this? A rectangle has its base on the x-axis and its upper two corner on the graph f(x) = 16 - (x^2). What is the largest area the rectangle can have?
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