I understand how the equations are set up but I can't seem to solve the maths to get the equilibrium constants. Is there something I am missing? Like I said, I am aware that X = 200 thus that value remains at that. Also, From the fourth equation K_{out} = Cl_{out}.
Homework Statement
With the 5 equations, the equilibrium contants can be calculated at the bottom. (See image)
My complication
I am aware that X = 200 thus that value remains at that. Also, From the fourth equation K_{out} = Cl_{out}. But, I cannot seem to work out the values. If not...
This is a question...
For the following question:
y^{'}=\frac{dy}{dx}=3y
I get the solution...
\int \frac{1}{3y} dy = \int dx
\frac{1}{3}ln y = x + c
y = e^{3x}+e^{3c}
However the textbook example says the solution is...
y = ce^{3x}
My question is would my answer be incorrect...
I live in UK. I haven't seen the ash but it's said that it's so high up that it doesn't effect people living here and thus it is not visible.
As for people stuck abroad, trains are very booked. Also, in France, there are train strikes which makes the situation harder...
Homework Statement
To find the reaction at A and B. (See image below)
Homework Equations
Moments and Area
The Attempt at a Solution
Area of load: (0.3)(6) = 1.8kN
Moments about A: -(6)(0.15) + RB(0.6) = 0 --> RB = 1.5kN
4. The error and question
I get the reaction force at...
Hi, I'm learning Bipolar Junction Transistor and need help to confusion which arise so I will keep posting questions which I don't understand to this thread. Thank you in advance. So my questions start:
When using hybrid pi model and t model, we determine the dc operating point first. In one...
Thank you.
Also, if the bottom left resistor branch didn't exist, then the current in the emitter would just be the current in the collector plus the current in the emitter?
I've got these two BJT circuits. I want to know if the result are the same. Are both circuits below same? Can the bottom left resistor be grounded and be same as the second circuit.
http://img21.imageshack.us/img21/2886/bjtt.jpg [Broken]
I will make this my discussion thread. I have many questions to ask which I will post here. Please keep checking. All help will be appreciated.
My first question is: For discrete signal, we use variable 'n' and for continuous signal, we use variable 't'. But is the convolution integral valid...
Hello PF Members! I'm revising amplifiers so will post question here occasionally on topics which I don't understand. This isn't homework question as I am asking for my benefit but if you wish for it to be moved, it's fine. :)
Here's my first question:
I've seen the circuit model for voltage...
When finding the particular integral, I understand that for:
y''+y'+y=e^{2x}, One would choose y=Ae^{2x}
y''+y'+y=x, One would choose y=Ax+B
But what am I supposed to choose if I have: y''+y'+y=xe^{2x}?
Homework Statement
For this given diagram, determine whether the particle is a proton or an electron.
2. The attempt at a solution
Considering at the point where it enters the material.
Using RHR, Velocity is downwards (First Finger), Field is outwards (Middle Finger), Thumb points left...
Homework Statement
Particles of the charges q1=+5e (at origin) and q2=-15e are fixed in place with a separation of d=0.24m. With V=0 at infinity, what are the finite (a) positive and (b) negative values of x at which the net electric potential on the x-axis is zero?
Homework Equations...
So, Am I correct to think that between the Cavity wall and the end of the conducting material, there is no field because charge enclosed is zero hence deriving the electric field through Gauss law would give zero electric field?
1. The Question
An isolated conductor of arbitrary shape has a net charge of +10\times10^{-6}C. Inside the conductor is a cavity within which is a point charge q = +3\times10^{-6}C. What is the charge on the outer surface of the conductor?
2. The attempt at a solution
On cavity wall...
Yes, some can be fat. But not all may be for the reason stated.
However, not every physicist is fat. Most are not. I can say they would eat less as they are more focused on their work thus are not fat.
... There are two sides to a coin.
It's a positive charge so field will be radially outwards. Is force also in those direction. If that is the case, then it will cancel out as there will be forces in opposite direction. :confused:
Homework Statement
A charge of 8\times 10^{-5}C is placed in an electric field (3000\b{i}-600\b{j})N/C. What are the (a) magnitude and (b) direction (relative to the positive direction of the x-axis) of the electrostatic force?
Homework Equations
F=Eq_0
The Attempt at a Solution...
The 'a' test, you can only put 'a' infront of 'x' and 'y' but not in front of the constant? Am I correct?
So...dy/dx= \frac{ay+ 1}{ax- 2}
And Not...dy/dx= \frac{ay+ a1}{ax- a2} which would lead to 'a' cancelling out.
I read that the 'Homogeneous Differential Equation' is one which has form \frac{\mathrm{d}y}{\mathrm{d}x} = f\left(\frac{y}{x}\right) but I came across one example which was \frac{\mathrm{d}y}{\mathrm{d}x} = \frac{x+y}{x+5y} and said that is 'Homogeneous Differential Equation' Too which has 'x'...
http://hyperphysics.phy-astr.gsu.edu/HBASE/electric/elesph.html#c2
I realized that there is a for a sphere of uniform charge, the electric field inside is not zero and a conducting sphere has zero electric field inside. Can the sphere of uniform charge also be hollow and solid, just like the...
Thanks Doc_Al. Amazing help as always. :smile:
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Another question:
Isn't the formula for Gauss law (When considering angle), EAcosx, so If the Gaussian surface is perpendicular, there would be no field as cos(90)=0. Why is it that when considering infinite sheet of...
I only know the gravitational theory briefly but I understood what you have said. :smile:
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Another question:
I understand that for a charged conducting sphere, the charge is built up on the surface thus there is no charge enclosed inside (if we are considering Gauss...
What is the potential used for? When is it used in context?
I know that it's related to Work by W=Ua - Ub.Work is the energy required to move a charge.
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Also, for coulombs law, there is a unit vector (r) in the equation. Isn't unit vector value always one?
(Thanks for...
Hello, I will post questions on this thread on Electric Field/Charge and other topics related to it. I'm studying it and am very weak at it thus any help will be appreciated.
For now, here's one question.
I've come across two equations for E which are E = (Kq)/(r) and E = (Kq)/(r^2). I...
Yes, I've taken multivariable calculus. I understand the further process to work out the moment of inertia but the limits and the density function that I have to insert confuses me.
Sorry for the confusion. It said y-z plane.
I have general question which need to be answered before I can understand steps which I have to do. There are:
When you are told that a solid is bounded by the coordinate plane and the plane x+10y + 2z = 5, are the limits considered to be 0-1 for x-axis, 0-10 for the y-axis and 0-2 for the...
Homework Statement
Calculate the gradient vector at the point S for the function, f(x,y,z)=x-\sqrt{z^2 - y^2}; S(x,y,z)=(4, 8, -6).
2. The attempt at a solution
\frac{\partial f}{\partial x} = 1
\frac{\partial f}{\partial y} = \frac{y}{\sqrt{z^2-y^2}}
\frac{\partial f}{\partial z} =...
I am making a script-m file to produce results of a formula in a Matrix output.
function s = calc(a, b)
i = [-a: 1: a];
j = [-b: 1: b];
k = i.^2 + j.*i;
A = [i' j' k']
disp('i j k'), disp(A)
But, it does not consider all combination. How can I make it stop at a 'i' value so...
Homework Statement
Find the shortest distance from the origin to the curve x^2+2xy+y^2=150.
Homework Equations
\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}
3. The problem I'm occurring
I'm not sure how to start is thus can't attempt it. I would have used the...
Great, Thanks.
Cool. I have a final question regarding this. If the voltage source and the resistor is in series, then it can be changed to current source? If the voltage source and the resistor is in parallel then it cannot be changed to current source?
It's ok. You have helped me a lot...
So, if I'm to find the thevenin resistance and have been given both voltage source and current source, is the best method to convert the current source to the voltage source then short circuit the current source?
Hmmm... Can you briefly explain what to do if current source and the resistor...