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So I'm a little confused about the nomenclature of this compound (CrO3). is it chromium (VI) oxide? chromic acid? and then Cr2O3 is just plain Chromium (III) oxide right?

Flame tests are used to test the color that a metal produces when heated and the electrons release energy when falling back to the ground state. This i understand, but why does the procedure only test the metal part of the salt? In other words, why does the anion part of the ionic compound not...

hte site of the sheet that my teacher gave me. it says "ss" for slightly soluble which he told us to assume meant insoluble. but i gues the chart isn't that reliable. because llokibng now at the other ones i see mostly blanks but one or two say soluble. thanks...

so if i cancel out spectators, it is a synthesis reaction (most sites agree that cuI2 is insoluble in water) Cu +2 (aq) + 2I -1(aq) ---> CuI2 (s) what i don't understand is why it is disproving my solubility rule (iodides are insoluble except for heavy metals, and copper isn't a heavy...

so this was the equation i was given: KI + CuSO4---> something i assumed it was k2S04 and CuI2 this is supposed to be either no reaction or double repleacement maybe having the whole equatoin helps? but the other three were correct, right?

are these soluble in water? Na2Cr2O7 (i think yes) (NH4)2Cr2O7 (i think yes) PbCr2O7 (i think no) CuI2 (no? whay is this disproving by rule that iodides and chlorides are soluble in water except for heavy metals?)

Today in class my chem teacher was insistent that 2Mg + O2 = 2MgO was a synthesis reaction. this I agree with. however, he was also adamant that this was not a combustion reaction, when it our textbook it specifically gave us this very same example as a type of combustion reaction. Question: is...

Well our teacher i think did not realize that so many of us would actually look into depth into this problem. he wanted us to assume because we know basically nothing about chemistry that based on the two reactants we would assume that it was double replacement. Thank you, again, a lot. This...

oh dear... i don't really know what that means.

thank you so much you've definitely helped to clarify this alot. final reaction: Fe(NO3)3 +KSCN = FeSCN(^+2) + K(^+1) + 3NO3(^-1)

my commbination i meant synthesis, sorry. so what is the KN03 considered? becasue it can't just dissapear. this was the reason i was confused between a double replacement reaciton and a synthesis reaction was becasue according to by obviously-limeted knowledge, i thought that becasue the Fe...

okay googled the same as you, just now i mean. the first thing i see in most of them is simply Fe + SCN = Fe SCN with some charge. But i don't understand about the charges, why wouldn't they simply balance themselves out, like Fe+ 3SCN = Fe(SCN)3, to have a net charge of 0? but this makes it...

i have looked at google. for several hours. I am coming up with nothing. I've seen some stuff about equillibrium and reversible reacitons, but nothing that i can classify as a definite answer.

Homework Statement When Fe(NO3)3 and KSCN reated, it immediatly turned red. my teacher says this si the stuff they use for fake blood in movies. My problem is, we must state the reaction type. Homework Equations the products, I am assuming, are FeSCN and KNO3 (i know I did not yet balance...