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1. ### Help Needed: Solving Mechanics Problem in Norway

I went ahead and solved it. There is actually one other step I used prior to summing moments about point C. You still have to isolate part of the structure as noted above which is the most important idea for this problem. I also found your vertical reaction at D looks like it is going in the...
2. ### Help Needed: Solving Mechanics Problem in Norway

the reactions at the supports look correct. you need to isolate the top portion of the structure (sum moments about C) to start getting answers.
3. ### Finding the reaction of a beam

Go through the statics tutorials. http://web.umr.edu/~bestmech/ [Broken]

Use virtual work. Set the deflections equal for each case and solve for P. I would guess this is how your instructor wants it to be solved and not just by manipulating existing tables.
5. ### Equilibrium of Coplanar Force Systems HW Problem

It is just making a free body diagram with the cable detached from the support. That is how I found the force in the cable. There are 3 steps; sum moments about A with the cable cut to get the cable force (note the cable is conveniently perpendicular to the platform), then sum vertical forces...
6. ### Equilibrium of Coplanar Force Systems HW Problem

I got it now, I had left out a cosine. Make a cut through the cable up at where it attaches to the top support. Then sum moments about point A using the vertical weights given in order to find the tension in the cable.
7. ### Equilibrium of Coplanar Force Systems HW Problem

Are the answers 143.6 and 445 and 71.8?
8. ### Corrosion of Steel: Equilibrium & Rate Drop

I believe the layer of corrosion protects it. Corrosion rates are higher in moving water because the corrosion covering is always being washed away.
9. ### Statics physics question

The question wants you to minimize the force in the cable "F". So in order to do that, you would want to find the angle and magnitude of the resultant of forces given already (like it says to do) then make "F" parallel with this force (at the same angle). So first break apart the given forces...

It sounds like you can approximate it as a uniform weight suspended cable problem. http://tinyurl.com/rmv6w
11. ### Designing a Bottle Cap Opening Device with Lever Mechanics

It is a cantilever beam, cantilevered on each side of the fulcrum. But don't try to equate the first class lever to a single cantilever of the entire lever length with the combined load on the end. That is why you got 4 times the moment the first time (8674).
12. ### Designing a Bottle Cap Opening Device with Lever Mechanics

"The original lever I calculated as a resistance of (about) 310N a distance 7mm from the fulcrum with an applied force of 85N a distance of 26mm from the fulcrum." For a second class lever, this is close enough to right. "After this I have multiplied each lengh of the side of the lever by...
13. ### Designing a Bottle Cap Opening Device with Lever Mechanics

Sorry, I tried to rearrange my last post to the end before you posted again. For a first class lever; http://en.wikipedia.org/wiki/Lever The max moment will occur at the fulcrum (not like in second class), so now Mmax=effort*26mm which is the same as the resistance*7mm. Now that you have...
14. ### Designing a Bottle Cap Opening Device with Lever Mechanics

I understood your opener to be a total of 26mm long. I don't understand how you are adding the 26 and 7 to get 33. What you should have is this: http://en.wikipedia.org/wiki/Image:C...ualization.png [Broken] Where the distance from the force to the first support (or resistance in your...
15. ### Solving a Statics Problem with F=80N

No, adding the force onto each bar will not equal the original force. Each component part of your equation is right, but I do not understand why you are trying to add the components. When you see a force written as F=#i+#j, the 'i' and 'j' are 90 degrees apart.
16. ### Designing a Bottle Cap Opening Device with Lever Mechanics

The required applied force is about 83.46N. The max moment is this force times the distance to the resisting force.
17. ### Designing a Bottle Cap Opening Device with Lever Mechanics

Get the section modulus (S) of the lever then solve for the bending stress, fb=M/S, this is the stress to compare to the yield stress of the material (for practical purposes). Most likely, yielding of a metal bottle opening lever from bending would be the failure mode and not shear. You would...
18. ### Calculating Pulley Forces: A Frustrating Problem

The box he is sitting on has only one cable at the left end so the box would rotate under his weight, unless there is some other information you are not giving. Is the box supposed to be in the air or sitting on the ground?
19. ### Truss Analysis

There are no zero force members for this load arrangement. JD would be a zero force member if there was not a load applied at D. There has to be equilibrium at each end of member BI. HI is balancing joint I and BC is working to balance joint B
20. ### Strengths Help

I believe that is the same as what I am calling the integration method: Either way, the assumption has to be made that the shear deformation is negligible compared to flexural deformation, or else you would need additional beam properties to get the correct solution.
21. ### Strengths Help

There are a couple of ways to solve an indeterminate beam problem. If you were not given the moment of inertia or modulus of elasticity, then the "flexibility" or "integration" method would be the one I would use to give you the approximate answers, since the E and I for this problem are likely...
22. ### Strengths Help

If "A" is a roller and has one reaction, and "B" is fixed for 2 translations and 1 rotation, then that is an indeterminate problem. You will need additional beam properties to be able to solve it.
23. ### Calculating Stress/Deflection in Cantilever Beam

To make sure I understand what you have; a constant rectangular cross section with a uniform horizontal force applied only along the top surface of the section and perpendiular to the longitudinal axis of the beam, and the beam has one end fixed and one end free. Your deflection can be...