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Hi, I don't get what the conditions below exactly means. Its which u they are talking about? Is the u the parent or children? Does it mean u = B? and the children are A,C,D? if u is in the quadtree rooted by v:NW then u:x < v:x and u:y ≥ v:y; Thanks,

2) Before I didn't draw it. But now I did draw it. its cos(60)? Because 20N acting 30º east of north and the other force is 20N acting 30º west of north

1) Direction the are going to the north? 2) Sorry, its cos(30) I overlooked the value. Should I do the whole calculation of it? Ok I have revise the forces and vectors addtion again and I will come back in few days!

I think it should be like this? 1) Both forces are showing in the same direction and together it makes 40 N? 2) R^2 = 20^2 + 20^2 -2 * 20 * 20 * cos(50)?

Sorry not really I do not understand. What should I do...

The magnitude will be Q? Now I tried to Now I tried to draw the forces into the triangle. The magnitude on the lower left will q or not?

Yes we had that long time ago. But how do I have to calculate the charges? I am bit confused now.

Because they have the same charge I just add each charge -> Q + Q + Q = 3 Q

Hello everybody To calculate the flux for the electric field I need the gauss law. There are two formula one with the integration over some area and the other is Q/e0. When do I have to use which one?

Thanks, for your reply. Hmm which one should I add? Didn't I already add those charges?

I don't what do you mean to point out those forces.

Thanks BvU I changed it and tried to follow!

Hi everybody, I tried to solve this problem but somehow I don't get it really. What I have to do. What I also know in this context is if its the same charge it will not attract otherwise if its the opposite charge it will attract. How do I have to calculate each charge on the corner? Question...