Search results for query: *

1. Intro Statics Problem

Thank you both very much. I have found the answer to the problem.
2. Intro Statics Problem

Unfortunately I have not done the vector cross product. Is it something I could teach myself in a few days? Thanks!
3. Intro Statics Problem

Homework Statement Here is a link to the problem that I am having issues with. http://tinypic.com/r/8zfb5h/7 Homework Equations F x perpendicular distance The Attempt at a Solution http://tinypic.com/r/1tamma/7 I have no idea where to go from there, or if I am even...
4. Help with Amount = RateTotal

SOLVED *Help with Amount = RateTotal* SOLVED SOLVED Homework Statement A pharmacist is mixing an 2.3% saline solution and an 9.6% saline solution to get 2.6 litres of a 5% solution. How much of the 2.3% solution is needed? Homework Equations Amount = Rate x Total The Attempt...
5. Solving an Equilibrium Problem Involving Torque: Need Help!

Well I found the total force of the scaffold including the weight of the painter and paint can was 1162N which both reaction forces equal. I guess I'll find out tomorrow. Thanks a lot for your help. It is grealty appreciated!
6. Solving an Equilibrium Problem Involving Torque: Need Help!

I came out with an answer of 428N on the side furthest from the painter/paint can and 734N on the other side. Does that look like the right answer? Thanks!
7. Solving an Equilibrium Problem Involving Torque: Need Help!

I made a diagram but I wasn't sure where to put the axis of rotation. I always thought the middle was best, but I have been told to use one end of the scaffold. I did that but I wasn't sure what to do next. Do I multiply the distances by the weights all the way down the 4.5m scaffold? Thanks.
8. Solving an Equilibrium Problem Involving Torque: Need Help!

Hello all I am working on some homework and I am having a problem with a question that involves torque. Here is the question. A 62.5 kg painter stands 1.35 m from one end of a 45.0 kg scaffold that is 4.50 m long. He has a 11.0 kg supply of paint 1.00 m from the end he is nearest to...