Yes, I tried that and am still not arriving at the right answer. 5.06/6.10 will give .82. If I integrate from -5.06t+3.05t^2 [0 to .82] + 5.06t+3.05t^2 [.82 to 1.2] I am still going to get :
5.06t +3.05t^2 [0 to 1.2]? Please help me out.
(-5.06+6.10t) - that is my answer after differentiating. Integrating the absolute value, I have 5.06t+3.05t^2 with integral limits of 0 to 1.20. When I put the values in the integral, I get 9.456 and when divided by 1.2, I get 7.88 which is not the correct answer.
I tried that but I am still not arriving at the correct answer. I arrive at a number far larger than it should be.
I cannot figure out what I am doing wrong.
Homework Statement
The position of a particle as a function of time is given by x = (-5.06 m/s)t + (3.05 m/s2)t2. Calculate the average velocity of the particle from t = 0 to t = 1.20 s.
-1.40 m/s (this is correct, from my calculations)
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