Would the first step be setting all those current sources to 0? Thus left with the remaining voltage source and the two resistors?
http://img820.imageshack.us/img820/2318/q2z4.png [Broken]
Homework Statement
Above given is the circuit I am supposed to simplify where the 1/5Ω resistor is the load. I'm unsure how to convert this circuit into an equivalent Thevenin Circuit.
Homework Equations
V = I*R (Ohm's Law)
The Attempt at a Solution
Using Microcap and it's...
Thanks, that was a mistake sorry
So basically use the integration rule and integrate te^t and then apply the Heaviside function?
I'm sorry, I'm not too confident with the Integral method, but..
integral{te^t} = (t-1)e^(t-st)
I'm not sure how to work from there.
[Googling Heaviside...
Homework Statement
Here's a quick sketch of the problem: http://prntscr.com/15ltr5
Essentially, Sugar Solution enters the first evaporator at 65°C and the water is boiled (to 100°C) so that a sugar concentrate comes out (bottom of evaporator) and saturated steam leaves the evaporator...
Homework Statement
120 mol/min of Propane (C3H8) is burned in the presence of air (21% O2 and 79% N2) in a furnace, two reactions occur:
Complete Combustion: 67%, propane is burned to CO2 and H2O
Incomplete Combustion: 18%, propane is burned to CO and H2O
Oxygen is supplied at 70%...
Pauli's Exclusion Principle...
each electron in an atom has a unique set of quantum numbers which must abide to a specific criteria...
where basically, any orbital can only contain a maximum of two electrons.
Ahh, when I actually bother to read my notes, I see that p-orbitals have 3...
Fair enough then, I have a Chemistry Prac in a bit so I don't have much time to calculate it, but, would the end result come out to as what I have gotten?
Or is there a mistake that needs to be corrected here?
Thanks, I appreciate the feedback.
This was my first homework question, I assumed it was correct since the tutorer looked at it and ticked me off, but, this is the question where I dragged my error from... Attempt #2
(t²-1)H(t-2) + (0-t²)H(t-3)
(t²-1) = (t-2)²+4(t-2)+4-1
H(t-2) [(t-2)²+4(t-2)+3]...
Thanks BruceW, unfortunately, I did not know that, going through my lecture notes and slides, there's no information on double checking our Laplace Transforms. Thanks a lot for telling me this, I'll Google it later to do a little bit more research on it!
And Ray Vickson, much appreciated, I...
Ah, it's a mistake carried over from a previous homework question I've done.
How would you go about substituting in values of 't' in order for it to validate my f(t) value?
For example...
cos(2∏(t-3))H(t-3) - cos(2∏(t-6))H(t-6)
And substitute in 0,
cos(2∏(0-3))H(0-3) - cos(2∏(0-6))H(0-6) is...
Homework Statement
Rearrange f(t) using Heaviside Step Function
Then Rearrange it so that the Laplace Transform can be written down
Then, Write the Laplace Transform of f(t)
Homework Equations
The Attempt at a Solution
So my first step is as follows...
Using the basic Piecewise Function...
Homework Statement
ODE: y'' + 4y' + 3y = f(t)
f(t) = (?? HELP - What's the mathematical term to describe these? I can't seem t o find it in my notes :cry: )
1, 0 ≤ t < 2
t², 2 ≤ t < 3
0, t ≥ 3
Write a brief description on how you would solve this ODE using Laplace transforms.
Also use the...
Homework Statement
http://prntscr.com/p7dxt
Here's a screenshot of the revision question.
Homework Equations
The Attempt at a Solution
Co-ordinates of each point
A, (0, 60, 0)
B, (40, 0, 0)
C, (-40, 0, 40)
D, (-60, 0, -60)
Position Vectors
rAB, 40i + -60j + 0k
rAC, -40i + -60j + 40k...
Hmm, I think I have actually interpreted this question wrong.
Is this image showing one 50kN load being distributed uniformly THEN being triangularly distributed. AND a 200kN point load? (I've been viewing it as two separate loads.
I got 225 by (50kN * 9m)/2 (Uniformly distributed load)
Homework Statement
Here is the Simply Supported Beam with a uniform and triangular load.
http://prntscr.com/jd6b2
Homework Equations
The Attempt at a Solution
Newest attempt: http://prntscr.com/jdu7d
Current Step: Shear Force and Bending Moment Diagrams.
Homework Statement
Consider a continuous, steady state process to produce hydrogen in which the following reactions take place:
C6H12 + 6H2O -> 6CO + 12H2 (desired reaction)
C6H12 + H2 -> C6H14 (undesired reaction)
In the process 220 mol of C6H12 and 840 mol of H2O is fed into the...
Alright, because this was a practice exam question (not homework), just thought that it'd give you all the information you'd need to know (and that the 'formula' for toluene wasn't given to you).
So there is no way you can do it without the molecular mass of Toluene? (or calculate it with the...
Homework Statement
A mineral slurry contains 3 components, solids, liquids and toluene.
The slurry has 20 wt% solids and 80 wt% liquid. In the liquid portion of the slurry the mole ratio of toluene to water is 1:5.67
Determine the composition of the slurry (solids, toluene and water) in...
Homework Statement
http://img507.imageshack.us/img507/6493/f7868b61c6cb4d6084fa5ba.png [Broken]
Homework Equations
The Attempt at a Solution
I've tried to deduct how my textbook has actually done this Thevenin Equivalent. No one in my class (that I've come into contact with...
Homework Statement
http://prntscr.com/fehze
There's a diagram with a rough free body diagram implemented.
Homework Equations
This is what I'm really unsure about.
The Attempt at a Solution
Finding Compression at BC: mg*sin(60) = 8495N
Tension AC = mg*cos(25) = 8890N
Not...
Homework Statement
http://prntscr.com/fcbm8
Find the centroid - All dimensions are in mm
Homework Equations
xbar = (A1X1+A2X2) / (A1+A2)
Similarly for Ybar I assume
The Attempt at a Solution
I got the y co-ordinate to be 20.428mm, and would assume that the x coordinate...
Homework Statement
http://img189.imageshack.us/img189/9131/22465062cfdd4934b51d7f5.png [Broken]
Hopefully the image isn't too difficult to decipher... Basically a beam balanced on to pin jointed pivots with 6 metres in between each one.
Homework Equations
ƩFy = 0
ƩFx = 0
ƩMP = 0...
Homework Statement
Two masses m1 and m2 (m1 > m2) are connected over a wedge shaped block. Assuming both inclined planes are frictionless along with frictionless and massless pulley, calculate an expression for the acceleration of the system.
Here's what it sort of looks like...
So instead of
ma = m*g*sinθ - μ*m*g*cosθ
it should be...
ma = m*g*sinθ + μ*m*g*cosθ
Which'll give me 1925N of force downwards...
Then doing the same thing, I'll have
3500 - 1925 = 200a
a = 9.625m/s^2
so basically, what I would do is use that equation I've got down there:
ma = m*g*sinθ - μ*m*g*cosθ
200a = 200*9.81*sin(30) - 0.35*200*9.81*cos(30)
a = 1.9315 down hill
Then... F = ma... = 200 * 1.9315 = 386.3
3500 - 386.3 = 200*a(uphill)
a = 15.5685m/s^2
Which is ridiculously fast, but...
Homework Statement
A cable is pulling a 200kg block up an inclined plane elevated at 30 degrees with 3.5KN of force. How fast is the block accelerating at?
θ = 30
g = 9.81
m = 200kg
μ = 0.35
F = kN
Homework Equations
F = ma
The Attempt at a Solution
Wasn't sure how to do this problem, I...
Yes, you are correct, I am trying to find the net work done. Since friction works in the opposite direction of which work does, I assume my friend is correct with his formula.
Work = mgx(μcos(θ) - sin(θ))
Work = Fx
Friction Force = -Fx
Well, I'm not 100% sure, but it's basically, the amount of energy done by something?
In anycase, is my Attempt correct?
My friend did it, and he got Work = mgx(μcos(θ) - sin(θ))
not Work = mgx(μcos(θ) + sin(θ))
Cheers
Homework Statement
Find the work done by friction force as it slides down an inclined plane in terms of...
m (Mass)
x (Displacement)
μ (Friction Coefficient)
θ (Angle of the inclined plane)
Homework Equations
ƩFnormal = mgcos(θ)
ƩFhorizontal = mgsin(θ)
ƩFfriction = μFnormal -...
Homework Statement
Find the initial speed (Vo) in Projectile motion in terms of
Gravity (g)
Height (H)
Range (R)
Homework Equations
Nothing has been given, however, have found these so far...
Initial Velocity = sqrt((1/2 * g * R^2)/(cos2θ * (R * tanθ + H))
And a few others which are...
It was recorded on a Digital Camera and I viewed it through Windows Movie Maker. I watched it again several times it's definitely within the 60 - 70 millisecond range.