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Would the first step be setting all those current sources to 0? Thus left with the remaining voltage source and the two resistors? http://img820.imageshack.us/img820/2318/q2z4.png [Broken]

Homework Statement Above given is the circuit I am supposed to simplify where the 1/5Ω resistor is the load. I'm unsure how to convert this circuit into an equivalent Thevenin Circuit. Homework Equations V = I*R (Ohm's Law) The Attempt at a Solution Using Microcap and it's...

Thanks, that was a mistake sorry So basically use the integration rule and integrate te^t and then apply the Heaviside function? I'm sorry, I'm not too confident with the Integral method, but.. integral{te^t} = (t-1)e^(t-st) I'm not sure how to work from there. [Googling Heaviside...

Homework Statement Laplace transform: te^t*H(t-1) Homework Equations L{te^t} = 1/(s-1)^2 L{H(t-1)} = e-s/s The Attempt at a Solution Using e^(at)f(t) -> F(s-a) with..e^(1t)H(t-1) We can get, e^(-1s-1)/(s-1) = e^(-s-1)/(s-1) [I think?] Thus applying tf(t) -> -dF/ds Derive[e^(-s-1)/(s-1)]...

Homework Statement Here's a quick sketch of the problem: http://prntscr.com/15ltr5 Essentially, Sugar Solution enters the first evaporator at 65°C and the water is boiled (to 100°C) so that a sugar concentrate comes out (bottom of evaporator) and saturated steam leaves the evaporator...

Homework Statement 120 mol/min of Propane (C3H8) is burned in the presence of air (21% O2 and 79% N2) in a furnace, two reactions occur: Complete Combustion: 67%, propane is burned to CO2 and H2O Incomplete Combustion: 18%, propane is burned to CO and H2O Oxygen is supplied at 70%...

Basically, this 1s3 2s3 2p6 3s2 3p1 violates Pauli's Law because of the third electron in the 2s orbital.

Pauli's Exclusion Principle... each electron in an atom has a unique set of quantum numbers which must abide to a specific criteria... where basically, any orbital can only contain a maximum of two electrons. Ahh, when I actually bother to read my notes, I see that p-orbitals have 3...

Homework Statement Here are the following Electron Configurations of Phospohorus 1. 1s2 2s2 2p6 3s1 3p4 2. 1s3 2s3 2p6 3s2 3p1 3. 1s2 2s2 2p6 3s2 3p2 3d1 4. 1s2 2s2 2p6 3s2 2d1 3p2 5. 1s2 1p6 2s2 2p5 6. 1s2 2s2 2p6 3s2 3p3 Questions: Which of these have non-existent orbitals...

Fair enough then, I have a Chemistry Prac in a bit so I don't have much time to calculate it, but, would the end result come out to as what I have gotten? Or is there a mistake that needs to be corrected here? Thanks, I appreciate the feedback.

This was my first homework question, I assumed it was correct since the tutorer looked at it and ticked me off, but, this is the question where I dragged my error from... Attempt #2 (t²-1)H(t-2) + (0-t²)H(t-3) (t²-1) = (t-2)²+4(t-2)+4-1 H(t-2) [(t-2)²+4(t-2)+3]...

Aha, that's not a problem at all, I'm assuming a lot of what you've just mentioned is something I'll be coming across in my course :)

Thanks BruceW, unfortunately, I did not know that, going through my lecture notes and slides, there's no information on double checking our Laplace Transforms. Thanks a lot for telling me this, I'll Google it later to do a little bit more research on it! And Ray Vickson, much appreciated, I...

Ah, it's a mistake carried over from a previous homework question I've done. How would you go about substituting in values of 't' in order for it to validate my f(t) value? For example... cos(2∏(t-3))H(t-3) - cos(2∏(t-6))H(t-6) And substitute in 0, cos(2∏(0-3))H(0-3) - cos(2∏(0-6))H(0-6) is...

Homework Statement Rearrange f(t) using Heaviside Step Function Then Rearrange it so that the Laplace Transform can be written down Then, Write the Laplace Transform of f(t) Homework Equations The Attempt at a Solution So my first step is as follows... Using the basic Piecewise Function...

Could you possibly do this... y'' + 4y' + 3y = f(t) y'' + 3y' + y' + 3y = f(t) d/dx [y' + 3y] + [y' + 3y] = f(t) let u = y' + 3y u' + u = f(t) Would that be correct?

Thanks for that.

Homework Statement ODE: y'' + 4y' + 3y = f(t) f(t) = (?? HELP - What's the mathematical term to describe these? I can't seem t o find it in my notes :cry: ) 1, 0 ≤ t < 2 t², 2 ≤ t < 3 0, t ≥ 3 Write a brief description on how you would solve this ODE using Laplace transforms. Also use the...

So do you mean like... ForceTotal = (eABi |FAB| + eACi |FAC| + eADi |FAD|)i + (eABj |FAB| + eACj |FAC| + eADj |FAD|)j + (eABi |FAB| + eACk |FAC| + eADk |FAD|)k Which then becomes something like... eACi |FAC| + eADi |FAD|)i = eABi |FAB| eACj |FAC| + eADj |FAD|)j = eABj |FAB| eACk |FAC| + eADk...

So essentially, balance out the forces... Basically something like... ForceTotal = ForceAB + ForceAC + ForceAD 2kN(eAB) = ForceAB = 1.1094i - 1.6642j + 0k

Homework Statement http://prntscr.com/p7dxt Here's a screenshot of the revision question. Homework Equations The Attempt at a Solution Co-ordinates of each point A, (0, 60, 0) B, (40, 0, 0) C, (-40, 0, 40) D, (-60, 0, -60) Position Vectors rAB, 40i + -60j + 0k rAC, -40i + -60j + 40k...

Oops, here it is: http://prntscr.com/jg37y

I've done the shear force diagram, is this right? Some reason I can't edit previous posts or the thread.

Alright I've redone it, http://prntscr.com/jdu7d The next step is to draw bending moment and shear force diagrams. I'll post when I've got them.

Hmm, I think I have actually interpreted this question wrong. Is this image showing one 50kN load being distributed uniformly THEN being triangularly distributed. AND a 200kN point load? (I've been viewing it as two separate loads. I got 225 by (50kN * 9m)/2 (Uniformly distributed load)

Homework Statement Here is the Simply Supported Beam with a uniform and triangular load. http://prntscr.com/jd6b2 Homework Equations The Attempt at a Solution Newest attempt: http://prntscr.com/jdu7d Current Step: Shear Force and Bending Moment Diagrams.

Homework Statement Consider a continuous, steady state process to produce hydrogen in which the following reactions take place: C6H12 + 6H2O -> 6CO + 12H2 (desired reaction) C6H12 + H2 -> C6H14 (undesired reaction) In the process 220 mol of C6H12 and 840 mol of H2O is fed into the...

Alright, because this was a practice exam question (not homework), just thought that it'd give you all the information you'd need to know (and that the 'formula' for toluene wasn't given to you). So there is no way you can do it without the molecular mass of Toluene? (or calculate it with the...

Homework Statement A mineral slurry contains 3 components, solids, liquids and toluene. The slurry has 20 wt% solids and 80 wt% liquid. In the liquid portion of the slurry the mole ratio of toluene to water is 1:5.67 Determine the composition of the slurry (solids, toluene and water) in...

Homework Statement http://img507.imageshack.us/img507/6493/f7868b61c6cb4d6084fa5ba.png [Broken] Homework Equations The Attempt at a Solution I've tried to deduct how my textbook has actually done this Thevenin Equivalent. No one in my class (that I've come into contact with...

How do I find them?

Yeah, I was probably thinking more about a centroid of a mass, but even then, there's still the donut which proves me redundant.

Homework Statement http://prntscr.com/fehze There's a diagram with a rough free body diagram implemented. Homework Equations This is what I'm really unsure about. The Attempt at a Solution Finding Compression at BC: mg*sin(60) = 8495N Tension AC = mg*cos(25) = 8890N Not...

This is what confused me, does this mean the centroid is not on the shape itself?

Homework Statement http://prntscr.com/fcbm8 Find the centroid - All dimensions are in mm Homework Equations xbar = (A1X1+A2X2) / (A1+A2) Similarly for Ybar I assume The Attempt at a Solution I got the y co-ordinate to be 20.428mm, and would assume that the x coordinate...

Homework Statement http://img189.imageshack.us/img189/9131/22465062cfdd4934b51d7f5.png [Broken] Hopefully the image isn't too difficult to decipher... Basically a beam balanced on to pin jointed pivots with 6 metres in between each one. Homework Equations ƩFy = 0 ƩFx = 0 ƩMP = 0...

Homework Statement Two masses m1 and m2 (m1 > m2) are connected over a wedge shaped block. Assuming both inclined planes are frictionless along with frictionless and massless pulley, calculate an expression for the acceleration of the system. Here's what it sort of looks like...

Should I actually be getting a figure here as an answer or an equation?

Mm, because, I have no idea really on how to implement static as well as kinetic friction into this problem :/

Could I use the same principles for this question? http://img844.imageshack.us/img844/6641/f5fec6746b9c42289610ba1.png [Broken]

Ugh all because of one mistake which I thought wasn't D: Thank you so much!

So instead of ma = m*g*sinθ - μ*m*g*cosθ it should be... ma = m*g*sinθ + μ*m*g*cosθ Which'll give me 1925N of force downwards... Then doing the same thing, I'll have 3500 - 1925 = 200a a = 9.625m/s^2

so basically, what I would do is use that equation I've got down there: ma = m*g*sinθ - μ*m*g*cosθ 200a = 200*9.81*sin(30) - 0.35*200*9.81*cos(30) a = 1.9315 down hill Then... F = ma... = 200 * 1.9315 = 386.3 3500 - 386.3 = 200*a(uphill) a = 15.5685m/s^2 Which is ridiculously fast, but...

Homework Statement A cable is pulling a 200kg block up an inclined plane elevated at 30 degrees with 3.5KN of force. How fast is the block accelerating at? θ = 30 g = 9.81 m = 200kg μ = 0.35 F = kN Homework Equations F = ma The Attempt at a Solution Wasn't sure how to do this problem, I...

Yes, you are correct, I am trying to find the net work done. Since friction works in the opposite direction of which work does, I assume my friend is correct with his formula. Work = mgx(μcos(θ) - sin(θ)) Work = Fx Friction Force = -Fx

Well, I'm not 100% sure, but it's basically, the amount of energy done by something? In anycase, is my Attempt correct? My friend did it, and he got Work = mgx(μcos(θ) - sin(θ)) not Work = mgx(μcos(θ) + sin(θ)) Cheers

Homework Statement Find the work done by friction force as it slides down an inclined plane in terms of... m (Mass) x (Displacement) μ (Friction Coefficient) θ (Angle of the inclined plane) Homework Equations ƩFnormal = mgcos(θ) ƩFhorizontal = mgsin(θ) ƩFfriction = μFnormal -...

After literally, 3 hours of arithmetic. We got the final answer.

Homework Statement Find the initial speed (Vo) in Projectile motion in terms of Gravity (g) Height (H) Range (R) Homework Equations Nothing has been given, however, have found these so far... Initial Velocity = sqrt((1/2 * g * R^2)/(cos2θ * (R * tanθ + H)) And a few others which are...

It was recorded on a Digital Camera and I viewed it through Windows Movie Maker. I watched it again several times it's definitely within the 60 - 70 millisecond range.