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    Double Angle Trig

    The problem is indeed sin(2x). It's really giving me a headache.
  2. F

    Double Angle Trig

    Homework Statement Sin2x-cosx=1 Solve for all x values between [0,2pi) Homework Equations Sin2x=2sinxcosx The Attempt at a Solution [/B] 2sinxcosx-cosx=1 cosx(2sinx-1)=1 I don't know what to do after this. It doesn't equal 0 so I can't set each factor equal to 0
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