someone is flying a plane and he is being chased and at the bottom of the loop his guages say he is traveling at 180km/h he is sitting on a bathroom scale which says he weighs 4 times what he normally does, what is the radius of the loop in meters?
[SOLVED] Projectile Motion Question
a swimmer moving at 1.80m/s dives off a pier and hits the water .80 m from the edge of the pier how high is the pier above the water
Vx=change X /change Time
change Y = Vyi . change Time +1/2 a . (change time)^2...
also is there a different formula to use for this when its on an angle, i know momentum before has to equal momentum after as does kinetic energy, mind you its not asking for kinetic, only speed, the balls are the same size so in the momentum formula we can get rid of the mass?, and its obvious...
2 identical biliards balls collde after a glancing collision determine the speed of the other ball,
MaVa + MbVb = MaVa' + MbVb' ?
The Attempt at a Solution
is this just as simple as the momentum formula before and after, or am I forgetting...
actually, it seems like the answer becomes 2.75kg which would mean in the direction of M1 which wouldnt be what we wanted so actually we could get it moving in the right direction by adding 2.8kg of weight to m2
does that make more sense then i can just figure out the acceleration of the...
so i do all that and if they equal the same the system wont move correct? so i know Fn is 417.87 for block 1 and i know the right force is 343.35N so to find left components i can go Fleft + Ff so 194.85 +175.5 that equals 369 though which would mean it would move down the ramp
alright and the other problem i had was simple it is a pulley question where 2 blocks are connected block one is on the incline and weighs 47kg and block 2 is on the other end of the pulley and weighs 35kg, theres 4 parts but the only one i need help with is a will the blocks move if m2 is...
so force dog cosØ is the same as the sin i mentioned when i edited my post when measuring off east? nice so FF=229 so i can go mu k equals 229/1422.45 which gives me .16 the book is saying .15x10(2) im confused
so we can say Ff = whatever the F of the dogs combined is or the - of it, and i dont know what i missed on the forces is it supposed to be sin? or the angle part should i be starting my measurements at E ? anglewise
this gives me
1) force of 79.98
2) force of 74
3) force of 75
[SOLVED] 2 more basic problems
3 dogs are pulling a sled with a combined weight of 145 kg the dogs are pulling
1) pulling at a force of 83N at 15.5(degrees) left of forward
2) pulling at a force of 75N at 9 (degrees) right of forward
3) pulling at a force of 77N at 12(degrees) right of...
ok what i did was used the formula F=mg sin(Theta) and punched in
20=20(9.81) sin (theta)
theta = 5.85
so when i get this angle is that the maximum it can be?
we have to design an entrance ramp for the new megamart. the maximum force customers will exert without complaint is 20N, ignoring friction at what maximum angle should the ramp be built assuming a full 20 kg grocery cart?
i've almost drawn at a blank it just seems like the question is...