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    Implicit Differentiation.

    Thanks statdad! so here's what I did, I substituted y' with -5x/3y and got y'' = (-15y + 15x(-5x/3y))/(3y)^2 = (-15y - 25x^2/y)/(3y)^2 = (-15y^2/y - 25x^2/y)/(9y^2) = (-15y^2-25x^2)/9y^3 But I still had to get rid of the x, so I used the original equation to solve for x^2, which...
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    Implicit Differentiation.

    Homework Statement Determine y'' when 5x^2 + 3y^2 = 4. The Attempt at a Solution So I found the first derivative using the power rule and chain rule, 10x + 6yy' = 0 Which I then solved for y', y' = -10x/6y = -5x/3y Next I found the second derivative using quotient rule...
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    Explaining which one has more potential energy.

    Explain which has more potential energy in each pair: water/glucose I think the answer is glucose since it's a bigger molecule and thus can store more energy than water. Am I right in thinking this?
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    Which one has the higher enthalpy, the reactent or the product?

    2Cl(g)→Cl2(g) ΔH = -243.4 KJ Which has the higher enthalpy under these conditions, 2 Cl (g) or Cl2 (g)? At first, I thought they would have the same change in enthalpy, because if I make it a reverse reaction, their magnitude will be the same. Then I realized that the signs...
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    Finding the derivative of f?

    Ack! I just realized that it doesn't matter where the negative sign is if there's only multiplication! I feel silly. Thanks for answering for allowing me to see this!
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    Finding the derivative of f?

    1. f'(x) = -sin(x) cos(sin(x)) 2. f'(x) = -cos(x) sin(sin(x)) 3. f'(x) = sin(x) cos(cos (x)) 4. f'(x) = -cos(x) sin(cos(x)) 5. f'(x) = cos(x) sin(sin(x)) 6. f'(x) = sin(x) cos(sin(x)) My feeling is that it's the first one, as it is the only one that has a negative sin, but I...
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    Finding the derivative of f?

    Homework Statement Find the derivative of f when f(x) = cos(sin(x)) The Attempt at a Solution I used chain rule on this function, and came up with this; -sin(sin(x)) times cos(x) Now either I'm doing something completely wrong, or I'm not seeing what it is equivalent to in the answers...
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    Finding the derivative of a function.

    I see, thank you very much! That makes much more sense now.
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    Finding the derivative of a function.

    Yes, sorry for the confusion.
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    Finding the derivative of a function.

    Differentiate: y = 4 8√x^2 Attempt to solve the problem. f ' (x) = 4(x^2/8) f ' (x) = 4 ( (2/8) x ^-6/8) f ' (x) = 4 ( (2/8) χ 1/x ^ 6/8) f ' (x) = 4 ( 2/ x^6) f ' (x) = 8/x ^ 6 I have no idea if this is the right answer, due to the fact that this is an online multiple...
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