Thanks statdad!
so here's what I did,
I substituted y' with -5x/3y and got
y'' = (-15y + 15x(-5x/3y))/(3y)^2 = (-15y - 25x^2/y)/(3y)^2 = (-15y^2/y - 25x^2/y)/(9y^2) = (-15y^2-25x^2)/9y^3
But I still had to get rid of the x, so I used the original equation to solve for x^2, which...
Homework Statement
Determine y'' when 5x^2 + 3y^2 = 4.
The Attempt at a Solution
So I found the first derivative using the power rule and chain rule,
10x + 6yy' = 0
Which I then solved for y',
y' = -10x/6y = -5x/3y
Next I found the second derivative using quotient rule...
Explain which has more potential energy in each pair:
water/glucose
I think the answer is glucose since it's a bigger molecule and thus can store more energy than water. Am I right in thinking this?
2Cl(g)→Cl2(g) ΔH = -243.4 KJ
Which has the higher enthalpy under these conditions, 2 Cl (g) or Cl2 (g)?
At first, I thought they would have the same change in enthalpy, because if I make it a reverse reaction, their magnitude will be the same. Then I realized that the signs...
Ack! I just realized that it doesn't matter where the negative sign is if there's only multiplication! I feel silly. Thanks for answering for allowing me to see this!
1. f'(x) = -sin(x) cos(sin(x))
2. f'(x) = -cos(x) sin(sin(x))
3. f'(x) = sin(x) cos(cos (x))
4. f'(x) = -cos(x) sin(cos(x))
5. f'(x) = cos(x) sin(sin(x))
6. f'(x) = sin(x) cos(sin(x))
My feeling is that it's the first one, as it is the only one that has a negative sin, but I...
Homework Statement
Find the derivative of f when
f(x) = cos(sin(x))
The Attempt at a Solution
I used chain rule on this function, and came up with this;
-sin(sin(x)) times cos(x)
Now either I'm doing something completely wrong, or I'm not seeing what it is equivalent to in the answers...
Differentiate:
y = 4 8√x^2
Attempt to solve the problem.
f ' (x) = 4(x^2/8)
f ' (x) = 4 ( (2/8) x ^-6/8)
f ' (x) = 4 ( (2/8) χ 1/x ^ 6/8)
f ' (x) = 4 ( 2/ x^6)
f ' (x) = 8/x ^ 6
I have no idea if this is the right answer, due to the fact that this is an online multiple...