F=ma can be applied, but that will only make the problem more complex. If you apply it to (flatcar + sand on it), you need to find the forces acting on the system. Sand falling on the flatcar exerts a force to it, because friction has to act on the sand to accelerate it until its velocity equals...
Homework Statement
Four thermodynamic processes A,B,C,D are shown in the picture. A and C are adiabatic processes. Pressure is held constant during B, and volume is constant during D. An engine run from A->B->C->D->... What is the efficiency of this engine (in terms of V1/V2)?
Homework...
Because J is a function of radius. I=\int { J\cdot dA } The second method looks fine.
For the second question: What is the enclosed current outside? Is it zero?
I do not understand the concept. Let the centrifugal forces on the two objects are F1 and F2. The rod will not rotate because net torque is 0. That is, F1r1=F2r2. That Does that mean we have to carefully adjust the positions of objects (before experiment) so that m1gr1=m2gr2? Then we conclude...
P1 is the initial pressure.
Look at the piston. There is a upward force produced by air inside, which equals P1 times S. Two downward forces are atmospheric pressure and weight. This gives the first equation, and the second one is similar.
Consider a small angle (delta theta) at the top of circle, and another one at the bottom. The rod length and angular velocity are constant. So moving through those two sections (two small angles at top and bottom) takes same time. But how much distance does the crank move? Looks different. So...
Sorry, I seemed to forgot that minus sign and messed up something. Your calculation is correct. cos\theta +(cos2\theta /n) has a range from -353/480 to 19/15, which is shown in the link.http://www.wolframalpha.com/input/?i=cos(x)%2Bcos(2x)%2F3.75&t=crmtb01 Put that back into the equation gives...
It looks like the acceleration varies with crank angle. Putting θ = 1 (rad) into the formula gives the acceleration at that particular position, not the maximum value.
I get 113.96 m/s^2 as the maximum acceleration from your formula. I think that's close but not very accurate, because that...
You may need this formula:
3sinx-4{ sin }^{ 3 }x=sin3x
Edit: It is possible to solve it directly using Cardano's method:
https://en.wikipedia.org/wiki/Cubic_function#Cardano.27s_method