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  1. J

    What is the de Broglie wavelength of this electron?

    The deBroglie wavelength is given by the relation \lambda = \frac{h}{p} where h is the plank constant and p is momentum. I'm assuming the number in eV you were given is the kinetic energy of the electron--you can look up its mass to get it in terms of momentum through T \text{(kinetic...