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  1. Jason-Li

    Comp Sci Laplace Transform of the input portion of this circuit

    So I have completed (a) as this (original on the left): I have then went onto (b) and I have equated T(s)=Z(s) as follows: and due to hence Does this look correct to you smarter people? Thanks in advance!! All replies are welcome :)
  2. Jason-Li

    Comp Sci Fourier analysis & determination of Fourier Series

    I am assuming that it would repeat? There is no symmetry that I can see? It would be odd if there was no 'missing' parts of the wave however Thanks for the reply
  3. Jason-Li

    Principal frequencies of a Waveform

    Hi HDG, Did you get the question correct? I got a final answer also of 97.271% How did you select the fields to create the scattergraph? Thanks for any help!
  4. Jason-Li

    Comp Sci Fourier analysis & determination of Fourier Series

    ANY AND ALL HELP IS GREATLY APPRECIATED :smile: I have found old posts for this question however after reading through them several times I am having a hard time knowing where to start. I am happy with the sketch that the function is correctly drawn and is neither odd nor even. It's title is...
  5. Jason-Li

    Transmission Line Coefficients & Definitions

    Hi again Rudeman, Was looking over my old working and found that in the final line of working is incorrect, unless I'm just being an idiot! = √ (31491.630+j9511.802) = 179.427+j26.506Ω Just to update this post.
  6. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    @FactChecker I think you give the materials too much credit, time and again I find inconsistencies or incorrect parts. Thanks for your help, it is much appreciated!
  7. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    @FactChecker Yeah in the materials the first graph is even (FIG.1) and the second graph (FIG.2) which is FIG.1 'shifted' is now odd, however I would say that it is neither odd nor even, unless as you say it is shifted down the 'Y' axis. There is however no mention of this Y-axis shift in these...
  8. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    Hi @bobob thanks for the help that really clears things up! I have tried bulking out the answer for each as follows, does that look correct to you? ( I realise this just builds on what you wrote ) a) Function is neither odd nor even. a0= V/2, an=0 b) Function is even hence will only...
  9. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    I thought it wasn't odd, the learning materials seem to be incorrect, it is implying that the diagram shown is odd - seems to be a recurring theme with this learning materials!
  10. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    @FactChecker Thanks a lot for the insight, not sure how I messed up the A0 figure. I have one query regarding a similar waveform in the learning materials that has been 'shifted odd' and I am unsure how this wave is 'odd' and not neither? wondering if you can give some insight. Thanks again.
  11. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    Ah I see what you mean I think, so I could maybe say the following: - The wave is neither odd nor even - a0 =0 & an = 0 Surely that can't be all there is?
  12. Jason-Li

    Fourier Analysis and the Significance of Odd and Even Functions

    @Connorm1 Hi all, having a look at this now and I am on the same boat as you were - I don't know how much detail they want and where to start with part (b). I see that you were trying to move the wave down the Y-axis to make it Odd, why not shift it to the right by T/4 so that it creates an...
  13. Jason-Li

    Transmission Line Coefficients

    Hi Babadag, I would've likely said the same however in my learning materials the below is stipulated. I then equated that each as appropriate. Any ideas?
  14. Jason-Li

    Transmission Line Coefficients

    Homework Statement Figure shows a 50 Hz, high-voltage, transmission line. The relationships between the sending and receiving end voltages and currents are given by the complex ABCD equations: where 'S' stands for sending-end and 'R' stands for receiving-end (a) Given the parameter values...
  15. Jason-Li

    Insertion Loss of a T-Network

    I'm trying to do this but can't seem to work it without a value for the voltage source. So i made the three nodes at the top V1, V2 & V3 and made the following equations V2/13 - V3/13 - V3/100 = 0 V2/13 - V1/13 - V1/75 = 0 V1/13 + V3/13 - V2/213 - 2*V2/13 = 0 Struggling to move on from...
  16. Jason-Li

    Insertion Loss of a T-Network

    Hi Berkeman, I'm trying to do the KCL using loop analysis to check but as I don't have values for voltage or current I can't seem to be able to work it out? It's the value of V I am struggling to cancel out.
  17. Jason-Li

    Transmission Line Coefficients & Definitions

    Thank you very much for the feedback.
  18. Jason-Li

    Insertion Loss of a T-Network

    Homework Statement Calculate the insertion loss of the T-network given the values: Rs = 75Ω Rl = 100Ω Ra = 13Ω Rb = 13Ω Rc = 213Ω The transmission matrix and Network are below: 2. Homework Equations The Attempt at a Solution Constructing the matrix: A = 1+Ra/Rc = 1+13/213 = 1.061 B...
  19. Jason-Li

    Transmission Line Coefficients & Definitions

    Homework Statement (a) State what is meant by a ‘distortionless’ and a ‘lossless’ transmission line. (b) A transmission line has the primary coefficients as given below. Determine the line’s secondary coefficients Zo, α and β at a frequency of 1 GHz. R = 2 Ω/m L = 8 nH/m G=0.5 mS/m C=0.23...
  20. Jason-Li

    A ##50\Omega## lossless transmission line impedance question

    Sorry to resurrect this post, just a quick simple one, Would Zin not have ohms as a unit?
  21. Jason-Li

    Two-port network z-parameters

    Yeah I was using V1 = z11*I1+z12*I2 with I2=0 so that V1 = z11*I1 which I rearranged to z11 = V1/I1 Just wondering if you could explain in algebraic terms what the original post of: z21 = V2 / I1 = V1 x (R6 / (R8+R6) ) x ( (R8+R6) / V1) = R6 = 6ohms; is?
  22. Jason-Li

    Two-port network z-parameters

    Sorry I'm not sure what you mean by type of equation? Basic ohms law or?
  23. Jason-Li

    Two-port network z-parameters

    Okay so Z11 = V1 /I1 with V1 volts would mean that current = I1. I think I maybe understand now. So Z11 = V1 / I1, voltage will run from top terminal 1 to bottom terminal 1 so will. = 14 ohms However for Z21 = V2 / I1, V2 contacts will be in parallel with the 6 ohm resistor, so Z21 =...
  24. Jason-Li

    Two-port network z-parameters

    Then Z12 = V1/ I2 , the current would act as in the first drawing so V1 = I2 * Z So: Z12 = (Z*I2)/ I2 = (6 * I2) / I2 = 6 ohms If this is the case then I now don't understand why Z11 is 14 ohms rather than the same as Z21 with 6, unless it is because from the perspective from Z21 the 8 ohm...
  25. Jason-Li

    Two-port network z-parameters

    Sorry, I assume you mean the red path in the second drawing? If so current would flow from top terminal 1 to bottom terminal one, so with both terminal 2s open the output voltage would equal the voltage across the 6 ohm resistor? Wait, so would: Z21 = V2 / I1 = (6 * I1) / I1 = 6ohms as I1...
  26. Jason-Li

    Two-port network z-parameters

    To try and understand the current flow path, I think I understand why Z12 = 6ohms as it passes only through the 6ohm resistor ( first crude drawing ) I would've though that Z21 = 14ohms as well as it would take the red path ( second drawing), can't quite understand why it is 6ohms unless it...
  27. Jason-Li

    Two-port network z-parameters

    Okay so if z12 = z21 V1 / I2 = V2 / I1 which I could rearrange to V1 * I1 = V2 * I2 V1 = (V2*i2) / I1 & V2 = (V1*I1) / I2 and I1 = (V2*I2) / V1 & I2 = (V1*I1) / V2 so I1 = (V2*I2) / ((V2*I2) / I1) I1*I1 = (V2*I2) / ((V2*I2) I1*I1 = (Z*I2*I2) / ((Z*I2*I2) I1*I1 = 0 ??? V1 = (V2*i2) / I1...
  28. Jason-Li

    Two-port network z-parameters

    Hi, sorry to be this a pain as I know this thread is a couple of years old but I'm now working through the same question, was just wondering if anyone could explain why for z21 V2 was changed to V1 x (R6 / (R8+R6) ) x ( (R8+R6) / V1) and how that equals 6 ohms? I'm looking to understand this as...
  29. Jason-Li

    Engineering Delta and star transformation of AC circuits

    I see, that does answer why it should be S = VI* thanks. Why is it you multiply by the conjugate? Would the negative Q value not mean it was leading?
  30. Jason-Li

    Engineering Delta and star transformation of AC circuits

    Sorry got a bit lost there, I follow you now and have gotten 7.5Ω. One other query regarding part (d), I have calculated out the same procedure as mentioned earlier in this thread using P = 3VI for total power consumed, which gives 11481.667-j11481.667. Could I assume that the 'imaginary'...
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