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    Magnetic Force Experienced by a Loop of Wire

    How about. ds x B = (wkydx - 2khx^2/w^2)k should i sub in my equation for y in for y?
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    Magnetic Force Experienced by a Loop of Wire

    hmm actually, ds = dxi + dyj dy=-2hx/w2 * dx dx/dy=w2/-2hx dx= -w2/2hx *dy therefore, ds = (-w2/2hx*dy)i + (-2hx/w2*dx)j
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    Magnetic Force Experienced by a Loop of Wire

    I wanna say di/dj = ds and so: y=h-hx2/w2 di/dj = dy/dx = -2hx/w2
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    Magnetic Force Experienced by a Loop of Wire

    I take the derivative of y with respect to x and voila?!
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    Magnetic Force Experienced by a Loop of Wire

    I'm not sure, I feel as if I need to express ds in such a way that it takes into account both the change in y and the change in x. Possibly a ratio?
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    Magnetic Force Experienced by a Loop of Wire

    This is what led me to believe that it was y=h-x2. Do you want me to say y=-ax2+h ? or am I completely approaching this incorrectly?
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    Magnetic Force Experienced by a Loop of Wire

    Ouf, nevermind, x=w and y=h-w2 make sense to me now. I reviewed a little bit of my highschool quadratic forms! :P
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    Magnetic Force Experienced by a Loop of Wire

    well in that case just y=h-w^2 but that doesn't make much sense to me, I was assuming something along the lines: y=-a(w+x)(w-x) ??
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    Magnetic Force Experienced by a Loop of Wire

    Yeah, isn't that what I have? y=h-x2
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    Magnetic Force Experienced by a Loop of Wire

    Homework Statement The problem is shown in the link below: http://postimage.org/image/do2b7xz0b/ [Broken] Homework Equations Biot-Savart Law's and dF=Idl x B The Attempt at a Solution My attempt is really just a mess. I essentially want to break it up into 2 segments. (1) Being...
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    E-field of a molecule on a point

    Homework Statement http://postimage.org/image/cky823nof/ [Broken] Homework Equations E=kq/r^2 The Attempt at a Solution I figured I would just find the electric field produced at point * by each individual charge and then add them. For example if I were to set E1 to be the top molecule...
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    * *Damped Harmonic Motion (Differential Equations)

    *URGENT*Damped Harmonic Motion (Differential Equations) A damped harmonic oscillator satisfies the following equation: d2x/dt2 = − 5x − 2dx/dt (a) By assuming a trial function of the form x = A e^qt, determine the solution of this equation "from scratch." Express your final answer as a real...
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    Charged Shape Described by a Function - Urgent

    I'm sorry but I'm really not following. I guess I could find mass by using m=(density)(volume) but I'm still uncertain on how to express the volume of this object.
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    Charged Shape Described by a Function - Urgent

    The Image has all the details: http://img38.imageshack.us/img38/3448/question3p.jpg [Broken] Uploaded with ImageShack.us I honestly I have no Idea as to where I should begin. Any hints on how to get started?
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    Triple Integral Problem

    Homework Statement the limits of integration are s[0,R] p[0,2π] z[0,L] respectively kp∫∫∫s/sqrt(s^2+(d-z)^2)dsdpdz Homework Equations The Attempt at a Solution You can double check my work but I'm pretty sure I got the first to integrations fine (with respect to s and p)...
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    Two thin rods on the x-axis

    Okay, I think I know what you mean. E=∫kdq/r^2 let dq=λdl and r =(a+x), the distance from the end of the rod to a +x value E=λk/(a+x)^2∫dl -integrating from -a-L to -a E=λk/(a+x)^2[(-a)-(-a-L)] E=λkL/(a+x)^2 How's that look? edit: I decided to use k rather than 1...
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    Two thin rods on the x-axis

    Sorry, I'm not following. The way I see it, when you take all the constants out you are just integrating dx/(-a-L+x)^2
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    Two thin rods on the x-axis

    x is suppose to represent where you are on the x axis. -regarding the bump, sorry it won't happen again.
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    Uniformly Charged Cylinder - Potential at distance d?

    Homework Statement Consider a uniformly charged solid cylinder of radius R, length L and charge density ρ. Find the potential at a distance d (> L/2) from the centre of the object, along the axis of the cylinder. Homework Equations V=∫kdq/r The Attempt at a Solution For me, it...
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    Two thin rods on the x-axis

    Homework Statement Two thin rods of length L lie along the x-axis, one between x = a and x = a + L, and the other between x = –a and x = –a – L. Each rod has positive charge Q distributed uniformly along its length. a. Calculate the electric field as a function of x produced by the rod on the...
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    Expressing a surface in cartesian coordinates from spherical

    Homework Statement The following equation describes a surface in spherical coordinates. θ =pi/4 Write the equation in the cartesian coordinates? that is, (r,θ,Ø) to (x,y,z) Homework Equations x=rsinθcosØ y=rsinθsinØ z=rcosθ r=sqrt(x^2+y^2+z^2) θ=cos^-1(z/r) Ø=tan^-1(y/x) The...
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    Using F=kvx in order to describe x as a function of t

    Nevermind I figured it out. For anyone who's curious. V=(kx^2/2m)+Vnaught dx/dt=(kx^2/2m)+Vnaught dx/((kx^2/2m)+Vnaught)=dt then integrate both sides.
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    Using F=kvx in order to describe x as a function of t

    Homework Statement The force acting on a particle of mass m is given by F=kvx in which k is a positive constant. The particle passes through the origin with the speed v naught at time t=0. Find x as a function of (t) Homework Equations F=ma a=(dx/dt)(dv/dx) The Attempt at a...
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    Uniformly Charged Ring Acting on a Particle

    Homework Statement Solve for the Electric force exerted on a Particle a distance z above a uniform ring of charge Q. Determine the potential energy of the charge where the charge lies directly in the center. Homework Equations F=kq1q1/r^2 The Attempt at a Solution Knowing E=F/q I...
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    Confusing Integral!

    Yes, that is the integral.
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    Confusing Integral!

    Not following.
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    Confusing Integral!

    Homework Statement int[x/((L/2)+d-x)^2] * the integral of x over [(L over 2 + d - x) all squared]* Homework Equations Integral chart The Attempt at a Solution I have done this so many ways with so many different answers. Could somebody who is without a doubt sure of the...
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    Electric Potential Energy of a Cube of 8 protons

    Thanks a lot! That really helps!
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