# Search results

1. ### What is the voltage across this capacitor, inductor and resistor?

Yes Yes! ok so now 1/(1/-24.1 + 1/414.7) Xp=-25.6 Therefore current through R is Ir = (270-25.6) = 244.4 That doesn't sound right...
2. ### What is the voltage across this capacitor, inductor and resistor?

Combined resistance would be using 1/((1/R1)+(1/R2)) which as far as I know works with impedance just like it does resistance. The reactance of L would be (2*pi*f*L) and the reactance of C would be (1/(2*pi*C)) Giving me: R=270 Xc=24.1 Xl=414.7 I could find the impedance of C and L by taking...
3. ### What is the voltage across this capacitor, inductor and resistor?

Thank you Dave, At risk of sounding well understudied is there a way to solve this with simple algebra? I was under the assumption there would be a variation on the existing equations used to find Z and X in simple RLC circuits which would eventually solve like a literal resistor network...
4. ### What is the voltage across this capacitor, inductor and resistor?

I can solve for the questions in completely series or parallel circuits however having the capacitor and inductor in parallel while the resistor stays in series is stumping me completely.