# Search results

1. ### Conservation Of Energy Problem

So this is the quaiton that i have problem w/: A 4kg bundle starts up a 30 degree incline with 128J of kinetic energy. How far willl it slide up the incline if the coefficient of kinetic friction between bundle and incline is 0.3? Because E_initial + Work = E_final and the Work done in the...
2. ### An gas molecule problem

Yes, I have fixed up on the equation. THx
3. ### An gas molecule problem

I am stuck in this gas problem: You are given a 10.00 gram solid mixture of Ca(ClO_3)_2 and Ca(ClO)_2. When this mixture is heated, both componds decomplse, releasing oxygen gas and leaving behind solid CaCl_2 When this 10.00gram mixture is sealed in a 10.0-Liter evacuated vessel and heated...
4. ### Finding the resulant from the product

I am new to Chem, and I don't quite understand how to solve this problem: Component of citrus fruits is the bitter compound limonin, which contains only carbon, hydrogen, and oxygen. When a 1.000-gram sample of limonin is subjected to complete combustion, 2.432 grams of CO_2 and 0.574 grams...
5. ### Wave nature of light problem

I see, so D sin (90) = (1) \alpha, which is the first minimum, and D has to be equal to the wavelength \alpha.
6. ### Wave nature of light problem

that sin of zero degrees is 0
7. ### Wave nature of light problem

Given a wavelength length \alpha, what is the maximum Width (D) of a single slit, which would have no diffraction minima? It seems like a proof problem to me and I am trying to get a head start. should I use D * sin (\theta) = m \alpha ?
8. ### Water wave

I find the angle to be 14.48 degree, but I didn't use the 2 meters that the question provdied. Am I missing something? I use d sin (\theta) = (m + \frac {1}{2} )(0.025m) where d = 0.05m, and m = 0 to find \theta.
9. ### Water wave

distance from crust to crust, gottcha
10. ### Water wave

how can i find the wavelength of the water wave? Is it simply just 1/2.5cm or 40m?
11. ### Water wave

This question is related to the wave nature of light from Giancoli: Water waves having parallel crests 2.5cm apart pass through two openings 5cm apart in a board. At a point 2.0m beyond the board, at what angle relative to the "straight-through" direction would there be little or no wave...
12. ### Magnetic Force

But how can i solve for l in order to calculate the Force by using F = I l B sin \theta ?
13. ### Magnetic Force

Ok, this problem shows up on my test today and I was wondering how you can solve it: A circular coil of wire has a diameter of 20 cm and contains 10 loops, internal resistance of 8 ohms, and the coil is placed in a 2.00T external magnetic field. When 1 volt is applied to the coil, determine...
14. ### Thin len problem

Oh, ray B travels in the shortest path but it takes the longest time because it stays more time in the len !
15. ### Thin len problem

But in this question, we have air- len (glass)(very short distance) - air, so the index of refraction doesnt affect much to the distance right
16. ### Thin len problem

the index of refraction
17. ### Thin len problem

Yes, Ray B is obvioulsy travelling in the shortest distance. But as we know that light is traveling at the speed of 3 * 10^8 m/s, what is significant about this problem? ;-)
18. ### Thin len problem

does the picture that i have attached interpert the question? I think this is a nice question to check my understanding of the topic :)
19. ### Thin len problem

This is a true of false question from my homework: Three light rays start out from a candle flame at the same time. To the right of the candle there is a lens, and to the right of the lens there is a screen. Ray A goes through the edge of the lens. Ray B goes through the center of the lens...
20. ### Converging lens

AHAHHAHHAHAHA. I feel myself really stupid now....can't even find the coeiffient term of a quadratic equation!
21. ### More Geometric optics

I dont know how the light would travel after entering the second len, the attachment shows where the rays are after the first len. It is drawn in scale, and I should expect the final image, which is inverted, have the same size as the original (becasue I got the mangification to be -1), and...
22. ### More Geometric optics

So when we are using the sign conversion, we only concern where the light is coming from in relative to the beginning right?
23. ### Converging lens

for i to be real and have two solutions, \sqrt{S^2 - 4Sf} must be greater than 0. So, s^2 - 4sf > 0 s^2 > 4sf s > 4f and we set s = i + o before, so we get the answer for the first two questiosn. But I don't know how you can get i = \frac{S \pm \sqrt{S^2 - 4Sf}}{2}, from i^2 +...
24. ### Converging lens

after \frac{1}{f} = \frac{1}{i} + \frac{1}{S-i} , I have f = \frac{si - i^2}{s} , and then i set the equation equals to zero: i^2 + fs - si = 0 , but i dont get how you can solve for i from i = \frac{S \pm \sqrt{S^2 - 4Sf}}{2}.
25. ### Converging lens

A bright object is placed on one sid eof a converging lens of focal length f, and a white screen for viewing the image is on the opposite side. The distance d_T = d_i + d_0 between the object and the screen is kept fixed, but the lens can be moved. Show that if d_t > 4f , there will be two...
26. ### More Geometric optics

now i have \frac{1}{-5} + \frac{1}{d_i} = \frac{1}{-10} and after calculation, i have d_i = 10cm it means that the final position of the image is 10 cm behind of the second len right? (when i say behind it, i mean the image would be in between the first and second len), and it is also a real...
27. ### More Geometric optics

so when I am loooking for the image position from the first len, i can basically ignore the existence of the second len. Is that what you mean?
28. ### More Geometric optics

Two lenses, one converging with focal length 20cm and one diverging with focal length -10cm, are placed 25cm apart. An object is placed 60cm in front of the converging lens. Determine (a) the position and (b) the magnification of the final image formed. I have a problem with this becasue...

Got it, thx
30. ### Another geomatric optics

hohoho nvm. you are right -3 and 3 will produce a different d_0, so if the two students are placing the obejct at exactly those location, then the magnification would be 3, even though one of them may be inverted. Thx