# Search results

1. ### I need help with this homework problem

Homework Statement Find three positive numbers whose sum is 12 and the sum of whose squares is as small as possible. Homework Equations The Attempt at a Solution I don;t even know how to start this one, this is a section from partial derivatives on the max and mins. Please i need guidance...
2. ### A model of basal metabolism.

Note: cal 1 is learning how to differentiate. cal 2 is learning how to integrate. I am in baby steps towards cal 2.
3. ### A model of basal metabolism.

∫ 85u-9/50∫ sin(u)
4. ### A model of basal metabolism.

I am taking calculus one and just learning integrals. Integral calculus is Cal 2 so no, I am not teaching my self integral calculus but I am trying to learn it. for the integral of g(u)=85=85u and for the integral of f(u)=-0.18cos(u)=-9/50sin(u).
5. ### A model of basal metabolism.

nevermind i got what you were doing. However upper limit of u is t=24 u=pi/12(24)=2pi and lower limit of u is t=0 u=pi/12(0)=0 12/pi ∫upper limit (2pi) , lower limit (0) 85-0.18cos(u)du than what?
6. ### A model of basal metabolism.

the ?'s are upper limit 24hours and lower limit 0 hours. I went right to the decimals because I did not know what du without taking the derivative was since is a fraction I was thinking in Quotient rule or product rule. I know i have to replace my du with what it is in my original integral...
7. ### A model of basal metabolism.

ok let me seee.... Let me know if i'm doing this right. du=0.26167dt ∫85-0.18cos(u)du=∫-sin(u)??? =∫85-0.18sin(0.26167t) (85-0.18sin(0.266767(24))-(85-0.18sin(0.266767(0)) Is that right??
8. ### A model of basal metabolism.

Homework Statement A model for the basal metabolism rate, in kcal/h, of a young man is given by the formula below, where t is the time in hours measured from 5:00 AM. What is the total basal metabolism of this man over a 24 hour period? R(t) = 85 - 0.18cos (Pi*t/12) ∫(0to24) R(t)dt= ...

Thank you.
10. ### Riemann sum limit

is not clear in part (a).
11. ### Riemann sum limit

deltax= 1-0/n=1/n than according to definition 2 the R endpoints formula is (a+ideltax)deltax so is i/n*1/n than substituting from x^3 we have (i/n)^3*1/n=i^3/n^3*1/n=i^3/n^4 which makes more sense. Now i just get rid of the 1/n^4 and put it in the other side of the summation and ta chan...
12. ### Riemann sum limit

I was having a hard time finding how did he got that 1/n^4.... LOL it was an ibvious mistake from part (a) even part (a) is wrong.
13. ### Riemann sum limit

I see... but he committed a mistake in the evaluation at lim n-> Ʃ i^3/n * 1/n is not lim n-> Ʃ i^3/n * 1/n is lim n-> Ʃ i^3/n^3 * 1/n
14. ### Riemann sum limit

Hey can someone explain to me how did he jumped from lim n-> Ʃ i^3/n * 1/n to lim n->1/n^4 Ʃ i^3??
15. ### Circular motion of ball and string

Thanks it worked!!!
16. ### Circular motion of ball and string

Homework Statement Part A : A 0.5 Kg ball is attached to a cord 80 cm long. The ball is whirled in a vertical circle at a constant speed. If the ball takes 0.4 seconds to go around once, what is the tension in the cord at the top and bottom of the circle? Part B How long does it take for...