Doesn't XGL currently run on top of X?
Ya compiz and xgl are good stuff. But currently does not support many video outputs, and dual screen. But fun to test out.
Anyone know where I could find a couple of chemical equations for Thorium. I need them for a project I am currently doing. I have not been able to find any.:uhh:
Thank you.:smile:
ya, amarok is my fav music player, and the xine engine is alot better quality than gstream and arts. I dont want qt libs on gnome, so now i use rhythmbox :grumpy: .
have you tried vlc?, best in my opinion.
ya, i know, i though no one visited the mathematics section, because i was only able to join it by using the search tool. Also, i put a note for someone to delete my post in the other section.:smile:
btw, i posted back on you reply.:tongue2:
Thats what I got, but I couldnt figure out how to solve the tan 2x = 2x. How would I be able to solve it?
I tried to graph it, but the points that came out, did not work in the equation.:yuck:
So, do I go with x=0 only?
edit: my teacher said, I was gonna use decimals on this problem.
edit...
Well, I got this equation f(x)=\frac{2\sin{2x}}{x} [-\pi,\pi]
So I took the 1st derivative, f'(x)=\frac{2(2x\cos{2x} - \sin{2x})}{x^2}
Then I set that equal to 0, and got 0=2x\cos{2x} - \sin{2x}
But I do not see how to get the critical numbers, I also tried to do double angle, but that...
Well, I got this equation f(x)=\frac{2\sin{2x}}{x} [-\pi,\pi]
So I took the 1st derivative, f'(x)=\frac{2(2x\cos{2x} - \sin{2x})}{x^2}
Then I set that equal to 0, and got 0=2x\cos{2x} - \sin{2x}
But I do not see how to get the critical numbers, I also tried to do double angle, but that just...
a= (-6/a^2) - (1/2)??????
i dont know, seems like this question could take up a long, long time. this is supposedly an ap free response question. im thinking this question, is a little too long, to be on a timed test.
hmmm, so
b = 3a^3 - 2a^2 - 4a - 8
b = a^3 - a^2 - 4a + 4
0=-2a^3 +a^2 +12
yuck, im sure this wasnt suppose to happen. :(
edit: somehow, i think im making it harder than it seems, looks like a very simple problem. :\
This somehow seems easy, but I cannot get the jist of it.
f(x) = x^3 - x^2 - 4x + 4
The point (a,b) is on the graph of f and the line tangent to the graph at (a,b) passes through the point (0,-8) which is not on the graph of f. Find the values of a and b.
okay so, ive spent about an...
I didnt go to school today, and so missed day of class, now i all lost someone help.
White light is incident normal to the surface of the film as shown below. It is observed that at a point where the light is incident on the film, light reflected from the surface appears green (lamda = 525...
im famous to, :). None of the websites that track ip can tell you exactly were people are, most are off a city or two, or not close at all if they use proxys as dduardo said.
norton is not even a antivirus i think, it does not detect alot of viruses, and takes most of the ram of you computer. I would do as said above, reinstall windows from a new cd, because sometimes store bought computers have alot of advertisement on them, and if you try to remove it windows...
While exploring a sunken ocean liner, the principal researcher found hte absolute pressure on the robot observatino submarine at the level of the ship to be about 413 atmospheres. The density of seawater is 1025-kg/m^3.
Calculate the gauge pressure p_g on the sunken ocean liner...
For #3, im assuming asteroid is at rest. So
Hero
m_{H}= m
v_{iH}= 0 m/s
Asteroid
m_{A}= 1000m
v_{iA}= 0 m/s
v_{fA}= 100 m/s
So momentum before = momentum after
0 = m_{A}v_{fA} + m_{H}v_{fH}