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    If F is ANY field then (x^m-1)|(x^n-1) in F[x] if and only if m|n.

    Hello. The question that I am having trouble with is the one found in the title. I will repeat it again here in the post. "If F is ANY field then (x^m-1)|(x^n-1) in F[x] if and only if m|n." I have determined that if m|n, then (x^m-1)|(x^n-1) as long as n >= 2 and s >= r >= 1. However, the...
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