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Thank you for all the help! Truly appreciate the way you help!! So why do we not hold the axes head direct in our hand, that will make us split faster?? My answer...there is a physical body limitation how fast we can accelerate our arm, not only from available torque....and in addition to...

OK, I got it. http://goo.gl/mMYBi" [Broken], I left it "open" so you can check the formulas in the cells.... Here is my take now on this comparison.... My theory is that, if one swing as hard as one can, with both "hammers", one use the same torque on both. And I can now see, :blushing...

http://goo.gl/mMYBi" [Broken]

Ok I gave it a try... I did set the torque to 25Nm that made a force on the mass at the end of the 1) 1.0m 2kg F=25N 2) 1.2m 2kg F=20.83N F=m x a a1=F/m=12.50 m/s2 a2=F/m=10.42 m/s2 With the radius of 1.0m alt 1.2m the distance for a 0.5PI rad angle will be d1=1.57m d2=1.88m...

so scenario 1. I=2x1.02=2Nm2? scenario 2. I=2x1.22=2.88Nm2? But how about the velocity after a 0.5PI rad swing??

that must be the mass*r2 Yes

It must be from the rotational work and Newton's 2nd law ??

Yes....lets say it is the head of a sledge hammer Thanks for the quick response!!:smile:

Homework Statement I have an angular acceleration question. I have two different scenarios I want to compare. The difference is the distance from rotational center point. The input torque is 1Nm in both scenarios. I want to accelerate a mass of 2kg over an 90 degree angle (0.5PI rad). My...