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  1. D

    2 Bullets, same mass, same v, fired at wood and steel block, which block has > v?

    The wooden block obviously. One, it has more final mass than the steel one, because it has the bullet plus the mass of the wooden block. And did we agree that the wooden block would have more velocity? because that would further corroborate my thinking. it would be much easier if we had actually...
  2. D

    2 Bullets, same mass, same v, fired at wood and steel block, which block has > v?

    because in an elastic collision that repels a bullet, thereby causing it to go back in the oppisite direction with an almost equivalent speed, the kinetic energy must be conserved. if the bullet was stopped and all the kinetic energy was transfered into the steel block, then maybe it could have...
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    2 Bullets, same mass, same v, fired at wood and steel block, which block has > v?

    "One hits a steel block, and bounces off. Both blocks are on a frictionless table. The steel block is a perfectly inelastic collison which causes the bullet to bounce of with the same v, and the block moves away with the same v." if it is an elastic collision, then kinetic energy must be...
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    2 Bullets, same mass, same v, fired at wood and steel block, which block has > v?

    no because it repelled the bullet. the steel block has no velocity. the wooden block does. If the steel block did move, and it also repeled the bullet at the same velocity, then it would have spontaneously gained energy, which is impossible.
  5. D

    2 Bullets, same mass, same v, fired at wood and steel block, which block has > v?

    Hmmm, I would want to say no. For an inelastic equation, where the bullet would go into the wooden block, the equation is m1v1 + m2v2 = (m1 + m2)vf. which is different from an elastic equation where everything remains constant. m1v1 + m2v2 = m1fv1f + m2fv2f (sorry my notation is a bit...
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    2 Bullets, same mass, same v, fired at wood and steel block, which block has > v?

    ahh we just did this in physics. what you would have to do is the mass of the bullet times the velocity of the bullet plus the mass of the block times its initial velocity (which would come out to zero) and set it equal to the mass of the bullet and block added together and your variable would...
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