So I simplified it. The projection onto the xz plane would be cos(a) if it was inclined in only one direction. And it would be cos(b) if it was inclined in the other direction so the compound projection would be cos(a)cos(b) correct? I like it. It might not be right... but I'll take it. By this...
Agreed. So are those three points I chose okay? so take the cross product them the dot product with the normal of the xz plane and then multiply by area?
I bet that would reduce wind resistance. :smile:
But honestly know one has any ideas? No Help? And why did this get categorized as "Precalculus" That makes me feel even worst. If an 8th grader can solve this and I can't. $5 to the first 8th grader that does. haha
I am a graduate of a 4 year university in Mechanical Engineering... But I graduated 3 years ago now and I feel like I'm slipping. I have a problem that I have come up with that I would like to be able to answer, but after a couple of days now I'm still stumped. A little help would be greatly...