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  1. C

    Interference and Diffraction of Light!

    thank you very much, would of helped if it was yesturday, i figured it out later on, but many thanks for helping. :biggrin:
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    Interference and Diffraction of Light!

    I didnt go to school today, and so missed day of class, now i all lost someone help. White light is incident normal to the surface of the film as shown below. It is observed that at a point where the light is incident on the film, light reflected from the surface appears green (lamda = 525...
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    Fluids at Rest!

    While exploring a sunken ocean liner, the principal researcher found hte absolute pressure on the robot observatino submarine at the level of the ship to be about 413 atmospheres. The density of seawater is 1025-kg/m^3. Calculate the gauge pressure p_g on the sunken ocean liner...
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    Momentum questions-please help-need them done tonight

    For #3, im assuming asteroid is at rest. So Hero m_{H}= m v_{iH}= 0 m/s Asteroid m_{A}= 1000m v_{iA}= 0 m/s v_{fA}= 100 m/s So momentum before = momentum after 0 = m_{A}v_{fA} + m_{H}v_{fH}
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    AMC test question

    o i see, i didnt understand the question. :rolleyes: , thxs though. :smile:
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    AMC test question

    thxs man, that really helped me out. :). How about the star one: In the five-sided star shown, the letters A, B, C, D and E are replaced by the numbers 3, 5, 6, 7 and 9, although not necessarily in that order. The sums of the numbers at the ends of the line segments...
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    AMC test question

    how about this one: Three circles of radius s are drawn in the first quadrant of the xy-plane. The first circle is tangent to both axes, the second is tangent to the first circle and the x-axis, and the third is tangent to the first circle and the y-axis. A circle of radius r > s is...
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    AMC test question

    wow, i didnt notice that, hmmm, thxs. :smile:
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    AMC test question

    This is not exatly homework, but it seems the best place to post it. Let A, M, and C be digits with: (100A+10M+C)(A+M+C) = 2005 A. 1 B. 2 C. 3 D. 4 E. 5 maybe some one can help me out on this, was one of the test questions i did not know how to do. :blushing:
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    Sine and cosine law in oblique triangles

    Okay, ya ur awnsers, are corrent. :smile:
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    Sine and cosine law in oblique triangles

    From my expiences with these types of problems, id say the shadow is where the tower is leaning.
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    Thermal Physics Help Needed

    I think his using correct formula, but first you must find the volume change: \frac {P_1 V_1} {T_1} = \frac {P_2 V_2} {T_2}
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    Thermodynamics in action

    Hmm, I didnt think of that. I think I can take it from here. Thank you very much. :smile:
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    Thermodynamics in action

    O and thank you for replying. :smile:
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    Thermodynamics in action

    Hmm, does not seem I learned those laws, onless my book and teacher are calling them by different names. O, and I asked to get this started, for example finding pressure on state 2. From what I see, is that the 150 kg weight does work on the gas? I might be wrong. But if so it does 1470 J, so...
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    Thermodynamics in action

    Okay, i found this problem to be pretty tough, maybe someone can lend me a hand. Theres a container with a piston, and theres a gas on the bottom of the piston. State 1 A=1.2 x 10^{-2}m^{2} T_1=0^{\circ{}}C V_1=1.5 x 10^{-3}m^{3} P_1=1.02 x 10^{5}Pa State 2 Theres a 150kg weight...
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    Please help with a uniform circular motion problem

    This might be that Im stupid, but shouldnt the angle be 90? Just saying 20s per cycle, 4 quadrants, 20/4=5?
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    A Momentum Problem

    Ya should be 6.5 m/s Momentum Initial = Momentum Final (MVi)of ball + (MVi)of vase = (MVf) ball + (MVf) vase
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    A Momentum Problem

    Im assuming they are not interested in friction, etc. Does not seem your awnser is right, because how could he throw it, and bounce back at a faster rate? hmmm, remember what Curious3141 said. Momentum initial = Momentum final
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    Physics AP problem (mechanics)

    Oops, I didnt even look at the graph, or read what she posted after your comment :rolleyes: . Point taken. :smile: Well seems she didnt even need our help, she had the awnser. Right after my post. "By the way, I got V1 = 4.727 m/s (to the right) and V2 = 21.27 m/s (to the left)."
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    Physics AP problem (mechanics)

    Srry, I was gone. I think it was an elastic collision. Because if it was not, then the awnser could not be determined. "Most collisions between objects involve the loss of some kinetic energy and are said to be inelastic. In the general case, the final velocities are not determinable from...
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    Physics AP problem (mechanics)

    ^ | I changed my post
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    Physics AP problem (mechanics)

    with the information given, I have, using momentum: (26)(.5) + (5)(0) = .5V_1 + 5V_2 momentum before = momentum after dont think one can do it another way, maybe if we see the graph it would change.
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    Finding Specific Heat of 2 substances mixed

    Srry for the confusion, I changed my post. :smile:
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    Finding Specific Heat of 2 substances mixed

    I c how, 1 cal/g*C= 4.184 J/kg*C, correct? Oops, 4.184 is already in KJ, I just noticed, that 1 cal/g*C=4184 J/kg*C. Thats whats started this whole question. Well thxs for all the help, and again I didn't mean to be rude. :smile:
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    Finding Specific Heat of 2 substances mixed

    apchem, I posted that before, because, dex said i got A, and told me to post my work. I said I did post it, and I didnt really care what the letter awnser was. Anyways thxs for the help, didnt mean to be rude.
  27. C

    Finding Specific Heat of 2 substances mixed

    So its (.02 kg)(68*C)c=(.1)(7*C)(1 ?) what is the specific heat measured in, isn't cal/g*C?
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