# Search results

1. ### Finding Critical Numbers

hmmm, ive heard of the newton-raphson algorithm, but we never learned it in class. ill check out that prog.:smile: thank you.

3. ### Finding Critical Numbers

ya, i know, i though no one visited the mathematics section, because i was only able to join it by using the search tool. Also, i put a note for someone to delete my post in the other section.:smile: btw, i posted back on you reply.:tongue2:
4. ### Finding Critical Numbers

Thats what I got, but I couldnt figure out how to solve the tan 2x = 2x. How would I be able to solve it? I tried to graph it, but the points that came out, did not work in the equation.:yuck: So, do I go with x=0 only? edit: my teacher said, I was gonna use decimals on this problem. edit...

6. ### Finding Critical Numbers

Well, I got this equation f(x)=\frac{2\sin{2x}}{x} [-\pi,\pi] So I took the 1st derivative, f'(x)=\frac{2(2x\cos{2x} - \sin{2x})}{x^2} Then I set that equal to 0, and got 0=2x\cos{2x} - \sin{2x} But I do not see how to get the critical numbers, I also tried to do double angle, but that...
7. ### Finding Critical Numbers

Well, I got this equation f(x)=\frac{2\sin{2x}}{x} [-\pi,\pi] So I took the 1st derivative, f'(x)=\frac{2(2x\cos{2x} - \sin{2x})}{x^2} Then I set that equal to 0, and got 0=2x\cos{2x} - \sin{2x} But I do not see how to get the critical numbers, I also tried to do double angle, but that just...
8. ### Ap Calculus help.

http://img.mauj.com/an/b/BowingSmiley.gif [Broken] thank you. very much. :) spent 2 hours on this and its late, time for sleep. thanks again.:smile:
9. ### Ap Calculus help.

so (2,0) is the only answer?
10. ### Ap Calculus help.

so i put in 2, get 4x^2 + 3x +6, looks like a mr quadradic to me.:grumpy: edit: roar!, mr quad come out a bad choice. so only one answer? (2,0)?
11. ### Ap Calculus help.

a= (-6/a^2) - (1/2)?????? i dont know, seems like this question could take up a long, long time. this is supposedly an ap free response question. im thinking this question, is a little too long, to be on a timed test.
12. ### Ap Calculus help.

hmmm, so b = 3a^3 - 2a^2 - 4a - 8 b = a^3 - a^2 - 4a + 4 0=-2a^3 +a^2 +12 yuck, im sure this wasnt suppose to happen. :( edit: somehow, i think im making it harder than it seems, looks like a very simple problem. :\
13. ### Ap Calculus help.

This somehow seems easy, but I cannot get the jist of it. f(x) = x^3 - x^2 - 4x + 4 The point (a,b) is on the graph of f and the line tangent to the graph at (a,b) passes through the point (0,-8) which is not on the graph of f. Find the values of a and b. okay so, ive spent about an...