From what i know, A field (which is actually force itself presented in a two-step process) does no work only if the displacement produced by that force is in a direction perpendicular to force. i.e.,
W = |F||d|cosΘ
If Θ =90°, w=0
Here. the displacement created by the electromagnets is in the...
Yes. I was indeed considering a wave related to E field. Scalar potential(electric) 'V'.
If you are actually removing imaginary portion, you will be neglecting some information in that wave. Which and why?
So this is what I understood based on your reply and my knowledge. Please correct me if I'm wrong.
1. Any wave is treated as a vector(may be becoz wave is energy propagated in a particular direction; magnitude is present; obeys vector law of addition)
2. A plane wave propogates in a plane whose...
I have two questions which has been troubling me:
1. How can we say that meaning of e^(jkR) is a spherical wave travelling in negative R direction. It can be viewed as polar form of vector with magnitude 1, but how a spherical wave?
2. When we take instantaneous value of a complex quantity ...
Thank you guys.
Isnt work = force * distance? By field value did you mean force? Thanks for giving insights into field concept.
Thanks a lot. You have actually cleared my doubt on this particular issue. But in normal cases charges wont exist alone....there will be a group of them no? So an...
Hello. Im having trouble understanding this particular statement found in one of my textbooks.
" Work done to move a charge along a line perpendicular to the field is zero"
The Attempt at a Solution
Field is a space around a charge where if we place any other charge, will...