Thanks for all the responses! :)
I guess I will sum things up to be sure.
For F=kx where F is applied force,
When the spring accelerates initially, F>kx (restoring force < applied force)
When the spring decelerates finally, F<kx (restoring force > applied force)
When the spring is at...
According to Hooke's Law, F=-kx where F is the restoring force, k is the spring constant and x is the length of extension/compression.
When an applied force compresses a spring, a restoring force will act in the opposite direction.
When a spring is compressed and is in equilibrium (not...
Thanks for the responses! Turns out that the answer to this question was simpler than I had thought.
The formula for centripetal acceleration at an instantaneous point in time is ac=v2/r.
The formula for centripetal acceleration for a changing tangential velocity over time is ac=(v(t))2/r.
What if the instantaneous linear speed is increasing? How would I be able to find out the centripetal acceleration's increase as the instantaneous linear speed increases? The formula only applies to an instantaneous point in time.
Additionally, what happens when the object is not moving in a...
When an object (e.g. racecar) moves around in circles with constant tangential velocity, constant centripetal acceleration is present.
What happens to the centripetal acceleration when the racecar is at rest, then increases its speed? I know that the tangential velocity increases due to the...