Find the area of the triangle with sides
A = (a1 ... an)
B = (b1 ... bn)
and A-B = (a1-b1 ... an-bn)
I don't even know where to start. I know how to do it in 3D with the cross product, but that obviously won't work for higher dimensions.
So I need help generalizing for Rn.
Hello fellow PF members
I was wondering how one would go about finding the lagrangian of a problem like the following:
A particle is constrained to move along the a path defined by y = sin(x).
Would you simply do this:
x = x
y = sin(x)
x'^2 = x'^2
y'^2 = x'^2 (cos(x))^2...
Why are you guys so fixated on that line??
That's not even the crux of the question I'm asking!
I obtained this differential equation from applying the Euler-Lagrange equation to the following function:
f(y,y') = (y')^2/y
That's how I know my reverse quotient rule is...
1. Homework Statement
Solve the following differential equation:
2. Homework Equations
2 y (y'')^2 + 2 y y''' y' -2 (y')^2 y'' = - (y')^2
3. The Attempt at a Solution
I don't know if the following is useful, but if you divide both sides by y^2, the LHS of the above...