I have to work this problem 3 ways, and I've gotten two, but am not sure about the third way.
the first way I worked by setting u = x^2 - 9
the second way I worked by setting x = 3sec(theta)
but the third way I have no clue, the book gave us a hint: Let x^2 - 9 =...
I've almost gotten through this one integral problem, but i've seem to have gotten stuck:
integral ((sqrt(4-x^2))/x) dx
i let x = 2sin(theta), and dx = 2cos(theta)d(theta)
sqrt(4-x^2) = 2cos(theta)
integral ((2cos(theta))/(2sin(theta)) * 2cosd(theta)
This one has me stumped, I dont even know where to start.
-Find the area of the triangular region in the first quadrant that is bounded above by the curve y=e^(2x), below by y=e^x, and on the right by the line x=ln(3).
Thanks for any help