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    Stuck on a trigonometry question

    1. Homework Statement Show that the exact value of tan°43' is \frac{\sqrt{5}-1}{2} 2. Homework Equations 3. The Attempt at a Solution tan2x = \frac{2tanx}{1-tan^{2}x} \frac{2tan31° 43}{1-tan^{2}31° 43'} From here, i got stuck or I'm doing it wrongly, i forgot how to do...
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