I am confused with the Kvp and Kep.
I know that In the x-ray tube, after heating the filament and the electron cloud if formed, then the step-up transformer is going to increase the voltage and reduce the current to produce a high potential difference to that electrons will accelerate from the...
Homework Statement
Ql: Which sound wave will have its crests farther apart from each other - a wave with frequency 100 Hz or a wave with frequency 500 Hz?
Homework Equations
Frequency= 1/ periodic time
The Attempt at a Solution
I did it like that:
I just found the periodic time for each...
Homework Statement
An ideal gas has a molar mass of 40 g and a density of 1.2 kg m-3 at 80°C. What is its pressure at that temperature?
Homework Equations
PV=nRT
R constant= 8.314
n= number of moles
T= tempreture in kelvin
density=Mass/ Volume
The Attempt at a Solution
i simply solved it like...
i am really surprised how could this be wrong, but this is in our lecture notes (college) and it's only 4 hours left for the exam. so is it hard to learn the parallel axis theorem
yeah i understood that the text says , it will rotate in the plane of x-y. but to make sure, it will move like a pin wheel right? and what about the R so? which R should i take?
yeah the sysytem will be rotating around z ( perpendicular to the page) as we have (x,y) fixed point, so the system will be rotating in the plane of x and y but around z. so the axis of rotation z is perpendicular to the pipe and at the center of it, so that why i used 1/12.
Homework Statement
Homework Equations
The Attempt at a Solution
i just dont know from where to take the R which is colored with brown, in the 2(MR^2), what is the R here exactly, because i took the radius of the sphere , but i get different answer althought it's near.
and regarding the pivot point, i think it's the one who will decide if it will rotate or not, i mean if it was at the center of the rod than there should be not rotation, but if the pivot is not in the center (not mentioned) then the distance of each force to the pivot won't be same so then i...
ohh yeaah, thanks everyone. i didn't focus on that point that is layning in the table!
so okay, i got the idea of the total f is equal to zero by the two forces, but still, why we have a torque??? why there is rotation when the two forces are with the same magnitude and opposite to each other...
Homework Statement
Homework Equations
torque= F*r*sintheta
total force on y= 0
The Attempt at a Solution
how come it will rotate in this situation?? espicially that he is ignoring the weight force of the rod! i knew that i ignored the mass of the rod when he said total force on y= F -F. if...
i thought that these are circles or (discs shape) because our professor said he will be providing us with necessary laws of MoI for each shape found in the diagram. so i said there is nothing other than the circles to make the hollow cylinder shell shape so that we use (I=MR^2). or is it that...
also, would you mind suggesting to me any useful videos on youtube or whatever about similar problems? or even a book including such problems, because i searched for somehow same ideas but couldn't find, it would be nice from you sir to help with it
okay, but what i don't get is what is the mass of the rectangular. now imagine i am working on the upper segment. the mass would it be 4kg?? i don't know really if the 4 kg is the mass of the whole rectangular or only the mass of the part of the circle which is included in the segment itself! if...
what about the mass of the rod, what will be the value I am gonna substitute in the 1/12(m)(l)^2 ???
and am I gonna separate the rods into three segments?
Homework Statement
Homework Equations
I= mr^2 for a hoop around a central axis
I= 1/12 (m)(l)^2 for thin rod about axis through center perpendicular to lenght
The Attempt at a Solution
I am totally confused. i said first that the three masses each will make a hoop shape so i found I=mr^2...
thanks so much your explanation was straight to the point.
I am literally appreciating everyone in this forum, who has the willingness to help without any return, every one of you is a lifesaver!
so the linear acceleration is made of two components :
1- the at the Tangential component, this is related to the magnitude of the velocity only. when there is change in vt there will be at.
2- the radial component which is directed to axis of rotation is related to the direction of the linear...
If talking about a particle rotating around an axis away from it by r. if the particle is moving with constant angular velocity ω. is the linear velocity constant or no?
Now what I know is that since we have Vt= ωr, so r doesn't change, as well as ω, so Vt is said to be constant. but I think...