Hello everybody.
I'm graduating with my bachelors in physics in a few weeks. My conundrum is that while I meet the GPA requirements for Magna Cum Laude, I am a few credits shy of the 90 matriculated requirement. If I were to extend my graduation date to the summer, I could take one additional...
While you typically don't need it for introductory 100 level physics courses, having a solid understanding of calculus will certainly help. Besides which you will need it eventually. Work on your understanding of derivatives and integrals. Those will be your bread and butter throughout most of...
Greetings everybody,
Right now I'm applying to graduate physics programs, but since it's an expensive process I'm trying to be at least a little selective in my approach. Since my research interests are in plasma physics, I've limited myself to schools with a program in such. So far I've...
When adding two vectors, keep the first one in place, and then put the tail of the second at the head of the first. Then you can draw from the origin to where that second vector's head is, and that's your new vector. Do the same for subtracting, but reverse the direction of the one you're...
It comes from Maxwell's addition to Ampere's Law. You can use that to solve for the magnetic field in between a capacitor, but they just did the work for you. Here's a link to the hyperphysic's page on Ampere's Law http://hyperphysics.phy-astr.gsu.edu/hbase/electric/maxeq2.html#c4
The magnetic...
Is that a line or a rod? The way the picture is presented it doesn't look like there is any flux, let alone a change in flux. Did you give us the entire problem statement?
Make sure you are strong on math. The better you are with math the easier a time you'll have in your classes. You probably haven't (and probably won't) cover calculus in high school, at least not much, but everything taught there will be an important foundation for later. Become especially...
kuruman is right. I didn't notice at first but your equation is slightly off. But, if that's what the book is giving you/asking you to use then so be it.
It says uniformly polarized, but what is the direction of polarization? Keep in mind it's actually a vector field, and you are dotting it with ##\hat r##.
For physics you need to be proficient in Calculus which consists of derivatives and integrals. I would say the bare minimum for beginner physics is being able to take a derivative and an integral (and knowing what it means to do so).
I can't remember the site, but there are statistics on where Physics grads go after earning their degree. I believe it also depends on whether you go for a PhD or not. But yes, most don't end up in academia, I think somewhere around 20% do.
That I can confirm. Physics is probably the most math intensive discipline outside mathematics itself. And it is certainly very hard. But I'd say it is worth it. Whether or not it is exciting is really up to what interests you. Personally I find learning about how the universe works to be...
If you want to get into any advanced physics with any depth, you'll be needing the entirety of Calculus (up through multivariable and vector calculus whether it be Calc 3 or 4 for your school), plus differential equations and linear algebra. A statistics class could also be particularly useful...
I'd say one of the worst common habits I see is students who go straight to the solutions manual if they don't understand the problem initially. Rather, it is better to think about it, drawing pictures and the like and thinking about the physics concepts you know, and then sleeping on it after...
I agree with mpresic. I found dynamics to be far easier than 300 level E+M. Of course, having a strong understanding of multivariable vector calculus before heading into either class can mitigate the difficulty.
To elaborate a little further, because ##\vec E## only involves a radial component, we choose a cylinder such that the area vector is always parallel to the electric field. Dotting these together removes the directional components and gives us simply ##\iint \left | E \right | dA##.
LaTeX. https://www.physicsforums.com/help/latexhelp/
My point is that you shouldn't be replacing ##\hat r## with anything. The electric field for a infinite line of charge is simply ##\vec E = \frac \lambda {2\pi \epsilon_0 s} \hat s## where s is the radial component. There is no need to change...
Think about what parts of the experiment are dependent on measurement. Generally speaking, each time you take a measurement, there is room for error if for no other reason than the tolerance of the measuring equipment.
Just because you don't have values for "a" and "q" doesn't mean you don't need to think algebraically. You have Coulomb's Law as one of your equations. Think about superposition and pick one particle. How will the other particles affect that particle?
I'm confused about what it is you're trying to accomplish. The magic of vector calculus is what gives us the Divergence Theorem, which is essentially Gauss' Law.
But as for where you might be going wrong, the first thing I noticed is you seem to be under the impression that ##\hat r## and...
As to which approach is more correct, both are perfectly fine. You'll find that problems in physics tend to have a great number of viable approaches. It's just a matter of which makes the most sense to you.
Your units aren't wrong per se, it's just strange that you would choose to convert to Joules instead of staying in eV which would be much easier in this case.
Yeah, I think I misinterpreted what the problem was asking him to find. It looks like it may be asking him to find when the activity will be potentially 10% less than the original calibration. Of course, you still want to use the lower curve and the higher curve for the worst case scenario.
The nice thing is that you can get the volume of displaced water into a convenient equation of depth of the sphere and it's far easier to work in is all. Since it sounded like accounting for the volume was your biggest issue. I can't say what you might have missed without first seeing what you have.