Just like to pick up in this old thread, still having trouble with the question.
Using what I have already done:
δrθ=(∂r/∂x . ∂x/∂θ) + (∂r/∂y . ∂y/∂θ) + (∂r/∂z . ∂z/∂θ) (1)
x=r sin θ cos φ and y= r sin θ sin φ z= r cos θ
Would (1) then become:
δyx= = ((sin...
Hi can anyone help me prove the result of W2 of the Pauli-Lubanski pseudovector :
This is very new to me and I've read I must use terms such as J13 and P3
Where totally antisymmetric symbol is defined by:
\epsilon1234=1 and \epsilon1243=-1
Consider a flat 2-dimensional plane. This can be described by standard Cartesian coordinates (x,y). We establish a oblique set of axes labelled p and q. p coincides with x but q is at an angle θ to the x-axis.
At any point A has unambiguous co-ordinates (x,y) in the Cartesian system. In...
Im told to consider the specific example of the vector:
Vμ = (3,1) in the Cartesian coordinates.
gμv is the metric tensor
Yes I believe they are bases, the question is based around raising and lowering the index in tensors
Transformation from Cartesian to spherical polar coordinates
x=r sinθ cos \varphi and y= r sin θ sin \varphi z=r cos θ
Show one example of:
∂z\alpha/ ∂xμ . ∂xμ/ ∂z\alpha = δ\alpha\beta
Now here is my answer:
δyx=(∂y/∂r . ∂r/∂x) + (∂y/∂θ . ∂θ/∂x) + (∂y/∂\varphi...
Basically Im asked to establish the probability that customer 1 will get a faulty brand A TV. Given that there are 1/3 of TV's in shop are A and probability of faulty TV is 0.2.
Hence: 1/3 x 1/5 = 1/15 or 0.06666666
Now the question switches to ask how many faulty brand A TV's will be...
So since the probability of a faulty TV for person 1 is 0.06666 or 1/15, after 11 customers the probability would be:
11 x 1/15 =0.733333
Since we cant have 0.7333 of a TV I just round this to 1. Therefore 1 faulty TV after 11 customers.
In a shop 1/3 of the TV's are brand A, the probability that a brand A TV is faulty is 0.2. What is the probability person 1 buys a faulty brand A TV?
Here's my attempt
Im not sure if it seems almost too easy but should I use the rule:
P(A) x P(B) = P(AnB)
A model for a single lane of traffic is given by the following pde
p dv/dx + v dp/dx + dp/dt = 0
v = kx/p
dp/dt = -k
Here is my attempt
v = kx/p
dv/dx = k/p
dp/dx = k/v
Substituting into original pde:
p (k/p) + v(k/v) + dp/dt=0...