it is given that 0<a<b
in this case why do we take bn or an common to make the inside element 0...and how do u guys take to solve this kind of situation how do u think?
to construct a barometer,a tube of length 1m is filled completely with mercury and is inverted in a mercury cup.the barometer reading on a particular day is 76cm.suppose a 1m tube is filled with mercury upto 76cm and then closed by a cork.It is inverted in a mercury cup and the cork is...
if a straight line c(-*81/2,-*81/2) making an angle 135 dge with x-axis,cuts the circle x=5cosm y=5sinm in points A and B ,find length of segment AB .
in the equation of line by solving i got y=-x
and tried to solve and ended up getting length of AB as 0 but the solution has...
This is not a problem with mathematics but a problem with representation of the number..probably the representation of decimal system has some loophole which produces this result..
consider that peter is sick
now there are two ways of informing his mom
i mean when data is sent from the network tower to the cell phone,can the data be detected by any other device?can the wave be concentrated in a particular direction(particular device) specifically.....
our lecturer defined MI as inertia of body in circular motion(i don't know anything about inertia)
except that it is something to oppose
my question is that
when M.I in circular motion depends on both mass and radius(distance from axis) of the body.
why MI is represented as mr^2 why is it...
i guess u guys are not getting the question,
see the diagram
it represents a car on 2 mountainous track in both the cases gravity acts downwards
a force mv^2/r acts upwards according to books so from newtons second law of motion we subtract both finding out the reaction force on the car by...
that means the force exerted by car on road is not centrifugal,so it is only the action force on the ground and nothing else?
i encountered a image:- http://img818.imageshack.us/img818/4782/anmol.png [Broken]
it states that reaction force on the car is mg-mv^2/r so here it is...
when we travel around a circular path we exert force on the path(ground)can be considered centrifugal force and petal which acts inwards,as a reaction to it.......it violates the rule that force of centrifugal is pseudo force..........
then what exactly is centrifugal force who gave this...