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  1. K

    Calculus problem with limits.

    That was a lot easier than it looked. I spent so much time trying to make it more complicated then it actually was. Thanks so much for your help.
  2. K

    Calculus problem with limits.

    I have this.. is that all? Is there a way I can evaluate sin(1) without a calculator or do I leave as is? \lim_{x \to 0} \ln\frac{(\sin(1)(17)}{16})
  3. K

    Calculus problem with limits.

    I got a number like ln.0854, but that was with a calculator which I'm not allowed to use. Not sure how I would do it otherwise
  4. K

    Calculus problem with limits.

    Homework Statement I have this problem on my calculus homework: \lim_{x \to 0} \ln\frac{(\sin(cos(x))(x^5+5x^4+4x^3+17)} {x^6+7x^5+8x^4+9x^3+16}) Homework Equations n/a The Attempt at a Solution I honestly have no idea how to go about this. We really haven't been shown...
  5. K

    Question about limits at infinity with radicals.

    Ah duh I got so into thinking it had to be complicated I didn't even think to just find the limit right there. Thank you so much that was so much easier than I imagined!
  6. K

    Question about limits at infinity with radicals.

    Ok I understand multiplying the numerator and denominator by 1/sqrt(X) to obtain: \lim_{x \to \infty} \frac{\frac{2}{\sqrt{x}}+{\sqrt{6}}}{\frac{-2}{\sqrt{x}}+\sqrt{3}} From this point do I multiply by the conjugate of the numerator? \lim_{x \to \infty}...
  7. K

    Question about limits at infinity with radicals.

    Homework Statement Find the following limit: \lim_{x \to \infty} \frac{2+\sqrt{(6x)}}{-2+\sqrt{(3x)}} Homework Equations n/a The Attempt at a Solution I know this shouldn't be that hard, but somehow I keep getting stuck on simplifying the equation. I think the first step is to multiply...
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