Sounds like maybe this forum isn't for me then, maybe when I'm better educated. Nothing was taken for granted, thanks to those who did help, I will study your advice and hopefully get it.
Why is this 4? Is it not 2 or am i seeing this wrong?
less than 1?
I'm struggling with the, almost, canceling down from factoring to
|x-2||x+2|< \epsilon/2
from this step I get really lost, as far as I'm aware the |x-2| is controlled by delta so i have to work with |x+2|
by this i use the...
That's the part I don't truely understand to be honest. The guide I read suggested as your trying to stay witching a small range 1 either side of the value (2) |x+2| is this wrong or have I (the more likely) misunderstood
Thanks but I don't quite get your hint
Not sure if this is right but thought I'd post my progress along with helpful sites in case somebody else has the same problem
http://math.stackexchange.com/questions/950493/stuck-on-an-epsilon-delta-proof-where-i-let-delta-be-a-minimum-of-two-values...
Sorry, I am really struggling with the precise definition of the limit. I have a specific question I'm trying to work out
lim(x->2) (4x2+2)=18
skipping the introduction part
any advice? I am just not sure how to get rid of the 2 value to re-arrange |(4x2+2)-18| to look like |x-2|
|x-2|<delta...
I'm trying to practise, precise definition of a limit (epsilon & delta)
Just to check I'm along the right lines here's a previous question to the one I'm stuck on
If epsilon > 0 then there is delta >0 ..... All that introduction stuff, then
Lim x-> 2 (3x-1) =5
Hence
|x-2| < delta then |3x -...
Hopefully this will be okay to follow apologies if not, not sure how to write equations on here yet.
>>
[sqrt(2+2h) - sqrt(2)]/h . [sqrt(2+2h)+sqrt(2)]/sqrt(2+2h)+sqrt(2)
>>
2+2h+[sqrt(2)sqrt(2+2h)]-[sqrt(2)sqrt(2+2h)]-2
h.sqrt(2+2h)+sqrt(2)
>>
cancels to
2h
h.[sqrt(2+2h)+sqrt(2)]
>>
giving, as...
I am really struggling with limits at the moment. Any help would be great! Thanks to anyone in advance if they take the time to read the rest of this.
Basically i am struggling with finding the limit when using direct substitution provides 0/0
I (think) am fine with limits that involve quadratic...
That's a much easier way to grasp the concept, thanks! Will get reading!
Sorry, I don't suppose you have any advice/similar PDF on the definition of a limit? I feel I'm getting there (although part of me feels it could all be wrong and I'm miles away)
Thanks! Just clicked into place now, remember him explaining this now. There is some frustrating gaps in my knowledge due to a non traditional route to higher education.
Thanks again!
Apologies if this is in the wrong place. I'm struggling to understand a step in finding a limit
Lim(x->0) x.sqrt(x+2) / sin(x)
Following the given solution I get to the point where it's all divided through by x to give
Sqrt(x+2) / sin x/x
Which as approaching 0 gives
Sqrt(2) / 1 = sqrt(2)...
"calculate the energy stored in the capacitor when the difference of potential between the two plates is 3V"
Apologies, yeah i meant CV2/2 but surly that is the same as 1/2 CV2, so using the equation:
Capacitance = 1.7 uF = 1.7x10-6 F
Difference of potential between the two plates = 3 V
//...
Homework Statement
Parallel plate capacitor, C = 1.7 uF
the difference between the two plates is 3 V
Find the energy stored in the capacitor
Homework Equations
U = 1/2 QV^2
The Attempt at a Solution
U = 1/2 (1.7x10^-6 F) (3V)^2 = 3.65x10^-6 J
Says the answer is: 1.53x10^-5 J
Not sure...
Thanks for all your help, I don't suppose you could reccomend a book/website to learn vectors? I have a physics book by Feynman that has a section on vectors I plan to read. Or would I get a better understanding of vectors from a mathematical viewpoint?
I'm assuming its the k component, that's the vertical part of i,j,k, right?
Thanks for the reply, i just seem to be struggling understanding the question to be honest. If it is the k component then surely the cross product would give 0 as well?
Homework Statement
a point particle is located in the position r=i+2j m . A gravitation (vertical) force of 1.5N acts on the particle. The torque about the origin is...
Homework Equations
thau = r X F = rFsin(theta)
The Attempt at a Solution
it's 0 right?
magnitude r = sqrt(1^2+2^2)m...
So to see the relationship between the particles and the speed of the container, you could use the following?
3/2 RT (=KE of gas molecules) + 1/2 mv2 (container)
but this doesn't obey,
PV = nRT
or P = T
If there is not a change in pressure, this will = no change in temperature but how can there...
That's great, thanks, its given me a better understanding. Sorry my question wasn't to clear, I guess I'm trying to understand the relationship between the speed of the container and the particles speed & energy.
Is there an equation to show the relationship? would the SUVAT equations be used?
Sorry last question, but even if their bulk velocity doesn't affect the relative. if the container is moving at a speed, when the particles collide with the surface of the container would this not affect the speed?
so would the KE gained not affect the energy needed for a successful collision...
Apologies if this isn't the right place but I saw a moderators post saying all questions should be posted in this section.
My physics knowledge is at a general A-level standard at the moment, I was curious about something and was just wondering if someone could help me find an answer.
My...