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    Archived What is the equivalent capcitance of this circuit! - Figured it out.

    What is the equivalent capcitance of this circuit! -- Figured it out. I have a Physics final exam in 2 hours and I'm re-reviewing things.... This problem DOESN'T make any sense!! 17. If C1 = 2 F, C2 = 3 F, C3 = 5 F, C4 = 6 F, the equivalent capacitance of the circuit is: A. 8.5 F is...
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    Index of Refraction Concept - Extremely Confusing

    I have just a few more questions regarding index of refractions and reflections... 8. A fly is 10 cm above the surface of a pond. How high above the water does the fly appear to a fish directly below (nair = 1, nwater = 1.333)? (A) 10 cm (B) 7.5 cm (C) 13.3 cm (D) 12.5 cm (E) fish cannot see...
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    Stressed about Physics Exam! Help with refractive index concept!

    Ohh I get it. So n_2sin(30°) = n_3sin(60°)\\n_1 = n_2 For n2, θ2 is small, so n2 must be larger. For n3, θ3 is large, so n3 must be smaller. Thanks!! I have just a few more questions regarding index of refractions and reflections... 8. A fly is 10 cm above the surface of a...
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    Stressed about Physics Exam! Help with refractive index concept!

    Or I should say... The index of refraction measures the bending of a ray of light when passing from 1 medium to another. The thicker the medium - the greater the "n", the slower the light passes, the smaller the angle (more towards the normal) The thinner the medium - the smaller the "n", the...
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    Stressed about Physics Exam! Help with refractive index concept!

    Hmm...Well I had to google this but, according to what found. Light (coming out of material n2) bends AWAY from the normal A LOT when it gets to medium/material n3. This means that there is not as much density in medium n3 to slow light down as there is in materials n1 and n2 (which are...
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    Stressed about Physics Exam! Help with refractive index concept!

    7. The figure shows the path of a portion of a ray of light as it passes through three different materials. What can be concluded concerning the refractive indices of these three materials. (A) n1 < n2 < n3 (B) n1 > n2 > n3 (C) n3 < n1 < n2 (D) n2 = n1 > n3 (E) n1 = n2 < n3 The...
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    Oh goodness... So what should M equal?
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    The answer has to be B then... Ok well since I know I got those top 3 questions wrong...I wouldn't mind moving on to the other questions I wouldn't mind you guys checking for me... I chose D…but I don't think it's right… I did this: Given: R = 10 cm f = -R/2 (since it's convex) = -10/2 = -5...
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    I forgot how to because I did this back in high school and my teacher (in college) just gave us a simple chart to follow and didn't emphasize the fact that we had to draw a ray diagram. :(
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    So the answer IS E. real (image on front), enlarged, inverted.
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    Ok but my answer is still wrong though... The answer for 3 would have to be D.
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    So basically all three of them are wrong?
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    Mirrors, Polaroid Films, Light/Wavelength help needed

    :(:(:( Please ease my aching soul by helping me with this... I submitted this assignment online and I don't know the answers yet or however many I got wrong. I chose 45 because I know unpolarized light becomes this after going through a polarizer: That single line is 180º, so I did...
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    Given 2 indexes of refraction, how do I figure out thickness of oil

    Given: noil = 1.16 nwater = 1.33 λviolet = 400 nm - Question 1: why did they give me this if i didn't have to use it? m = 1 (first order) - Question 2: what do they mean by the term "first order"? I never understand :( t = ? Equation to use: 2noilt = mλ t = mλ/2noil t = (1)(400 nm) / 2(1.16) t...
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    Trouble determining the slope of the graph!

    Fot Question 2, I got the slope correct. It's 0.0339. But how do I find B, given L = 4.1 cm? This is what I did (I chose any value for F and I from the table): B = F/IL B = (0.0158 N) / (0.48 A)(0.041) B = 0.0158/0.01968 B = 0.802 N/a "INCORRECT" :(
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    Trouble determining the slope of the graph!

    Oh it worked! Thanks!! So all I need for B is do, B = Faverage / IaverageLaverage B = (0.02075)/(892.75 mA)(0.02525 m) B = 0.02075/22.54 B = 0.000920586 B = 920 T
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    Trouble determining the slope of the graph!

    I submitted "0.008 N/cm" but webassign says it's incorrect :( :'( That must mean my B is wrong too... :(
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