Pressure at the surface is 1 atm = 101 kPa.
Pressure at 11 m = 2.09 atm = 212 kPa.
V2 = V1*(T2 / T1)*(P1 / P2)
V2 = (8.18 cm3)*(289 K)*(212 kPa / 101 kPa)
V2 = 4962 cm3
That can't be right... What do I need to have everything converted to?
Do I convert them to the following:
T1 = 16.0ºC +...
Homework Statement
A scuba diver releases a 2.50-cm-diameter (spherical) bubble of air from a depth of 11 m in a lake. Assume the temperature is constant at 16.0ºC, and the air behaves as a perfect gas. How large is the bubble when it reaches the surface?
Homework Equations
V2 = V1*(T2...
Homework Statement
A 1.450 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a new equilibrium position, x= 0.290 m.
a.) Find the effective spring constant of the system.
b.) The glider is...
1. Homework Statement :
A simple pendulum has a mass of 0.25 kg and a length of 1.0 m. It is displaced through an angle of 5.0° and then released.
1. What is the maximum speed?
2. What is the maximum angular acceleration?
Answer: 0.855 rad/s2
3. What is the maximum restoring force?
Answer...
Okay. So to find pressure difference:
P = 8 * η * L * Q / pi * r4
P = 8 * (0.004 Pa*s) * (0.0407 m) * (6.5 x 10-8 m3/s) / pi * (0.000194 m)4
P = 19023 Pa
If that is correct, how do I find height from this?
Homework Statement
1. You put a tomato into a vessel of salty water - it floats. Now you pour olive oil into the same vessel. Which one of the following statements is true?
a. More of the tomato will be above the surface of the water.
b. The tomato will stay at the same height.
c. Less of...
Homework Statement
A patient is to be given a blood transfusion. The blood is to flow through a tube from a raised bottle to a needle inserted in the vein. The inside diameter of the 4.07 cm long needle is 0.388 mm and the required flow rate is 3.90 cm3 of blood per minute. How high should the...
So if I recalculate, fixing my errors and taking out 0.5:
t = V / Q = 8 * V * h * L / (pi * r^4 * Dp)
t = 8 (0.006 m^3)*(0.2)*(0.12 m) / (pi * (0.026 m)^4 * (824 Pa))
t = 0.974 sec
Still wrong.
You can calculate the pressure difference:
Dp = rgL
Dp = (700 kg/m^3)(9.81 m/s^2)(0.12 m)
Dp = 824 Pa
And the time it takes for the oil to flow through is the volume of the oil divided by the flow rate:
t = V / Q = 8 * V * h * L / (pi * r^4 * Dp)
t = 8 (0.006 m^3)*(0.2)*(0.012 m) / (pi *...
So I calculated the equation using pi:
t = V / Q = 8 * V * h * L / (p * r^4 * Dp)
t = 8 (0.006 m^3)*(0.2)*(0.012 m) / [ pi * (0.5)*(0.013 m)^4 * (82.4 Pa) ]
t = 1.9492 sec
But it is still incorrect... Any ideas?
Yes, I wrote it down right. I will 12.8, but I'm not sure if it'll make a difference. But anyways, thank you for all of your help. =) I really appreciate it.