I think im undertsanding the concept. I need to find the amount of energy to go from
10°C of water to -7°C of ice .
Q_{ice} = mL_{c}, where m = mass and L_{c} = 3.34 X 10^{5}
okay, to make sure I'm on the right track.
Q_{water} + Q_{ice} = 0, where Q = mc delta T.
I then solve for T, plug back into Q_{water} then solve for m?
1. 30 kg of water at 10°C is mixed with 360 kg of ice at -7°C. (The heat capacity of water is 4190 J/(kg * °C), that of ice is 2090 J/ (kg *°C), and the heat of fusion of water is 3.34 * 10^{5} J/kg
1. What mass of water freezes?
Homework Equations
none that I know of.
The Attempt...