A 2319kg car is moving down a road with a slope grade of 11% and slowing down at a rate of 3.8m/s^2.Find the direction and magnitude of the frictional force ( define positive in the forward direction ie down the slope)
So the equation I have is f= ma+ mgsinθ. For my angle I get...
a 1000 kg car is moving down a road with slope (grade) of 15% while slowing down at a rate of 3.7m/s^2 .What is the direction and magnitude of the frictional force?(define positive in the forward direction)
Using f=ma
I have the mass 1000 kg, the acceleration 3.7m/s^2, and slope 15%...
fictional force problem....given a slope(grade)???
A 1000kg car is moving down a road with a slope(grade) of 15% at a constant speed of 15m/s. What is the direction and magnitude of the frictional force?
So...
V= 15m/s
a= 0 (constant)
The slope really throws me off..I don't know...
you throw a ball straight up in the air with a speed of 7.25m/s. The moment the ball leaves your hand you start running away at a speed of 2.59m/s. How far are you from the ball the moment it hits the ground.
So I've gotten better at these kinematics equations but this one has too many...
*confused
A car speeding up from rest to constant accel. travels 100 meters in 6.04s. How far did it travel in the first 2.37 seconds?
So I figure if I divide distance by time 100/6.04 it will give me the velocity 16.5m/s. And since distance = vt I would do d=15.6*2.37 which equals 37.03m but...
I know that something with double the speed will travel 4 times as far. So does that mean you take the given distance and multiply it by 4? or take the distance and multiply it by 2 and square it? for example if its 3 meters would it be 3*4 or (2x3)^2
A car speeding up from rest to constant accel. travels 100 meters in 6.04s. How far did it travel in the first 2.37 seconds?
So I figure if I divide distance by time 100/6.04 it will give me the velocity 16.5m/s. And since distance = vt I would do d=15.6*2.37 which equals 37.03m but this is...
Need help with "motion" question..please!
Homework Statement
you are sitting in a car that is stopped. The moment a biker passes you, you start accelerating at 3 m/s2, while the bicycle continues to move along at a constant speed of 9 m/s. After what distance will you catch up with the...