What is the equivalent capcitance of this circuit! -- Figured it out.
I have a Physics final exam in 2 hours and I'm re-reviewing things....
This problem DOESN'T make any sense!!
17. If C1 = 2 F, C2 = 3 F, C3 = 5 F, C4 = 6 F, the equivalent capacitance of the circuit is:
A. 8.5 F is...
I have just a few more questions regarding index of refractions and reflections...
8. A fly is 10 cm above the surface of a pond. How high above the water does the fly appear to a fish directly below (nair = 1, nwater = 1.333)?
(A) 10 cm
(B) 7.5 cm
(C) 13.3 cm
(D) 12.5 cm
(E) fish cannot see...
7. The figure shows the path of a portion of a ray of light as it passes through three different materials. What can be concluded concerning the refractive indices of these three materials.
(A) n1 < n2 < n3
(B) n1 > n2 > n3
(C) n3 < n1 < n2
(D) n2 = n1 > n3
(E) n1 = n2 < n3
:(:(:( Please ease my aching soul by helping me with this...
I submitted this assignment online and I don't know the answers yet or however many I got wrong.
I chose 45 because I know unpolarized light becomes this after going through a polarizer:
That single line is 180º, so I did...
For the slope, I got 0.4532 and for B, I got 74.09, but they're both wrong! And my excel program keeps crashing everytime i try to print screen it!
This is really urgent and I don't know who else to turn to because this is due very very soon and I'm desperate!!
Also, what about this one:
In each of parts (a), (b), and (c) of the figure below, find the direction of the current in the wire that would produce a magnetic field directed as shown.
part (a) right to left
part (b) out of the page
part (c) lower left to upper right
So, the right hand rule...
The two wires shown in the figure below are separated by d = 8.0 cm and carry currents of I = 4.85 A in opposite directions.
d = 8 cm = 0.08 m
d = 8 cm = 0.08 m
r = 0.08/2 = 0.04 m
2d = 21.6 cm
I (up) = 4.80 A
I (down) = 4.80 A
(a) Find the magnitude and direction of the net magnetic field...
Right Hand Rule doesn't work for this problem???
Consider an electron near the Earth's equator. In which direction does it tend to deflect if its velocity is directed in each of the following directions?
I DON'T get this!
I know they're basically saying this:
Velocity of electron...
2. Three loops of wire move near a long straight wire carrying a current as in the following figure.
(a) What is the direction of the induced current, if any, in loop A?
c. No current is induced. (ANSWER)
WHY IS "C" THE ANSWER???? I don't...
Omggg :( Determining voltage between point a and b given R = 40 ohms
This is what I did for part A:
1) ΔVrms = Vmax(1/√2)
ΔVrms = (145)(0.707)
2) Ztotal = √[R² + (XL - XC)²]
XL = 2πfL
XL = 2π(40)(185 x 10^-3)
XL = 46.49
XC = 1/2πfC
XC = 1/[2π(40)(65 x 10^-6)
How do I go about solving this?
Whenever I see a capacitor diagram/an image like this i always freak about because
1) I don't know what to ask myself when I see it
2) I'm not sure I know what's going on - other than the fact the the | | means: +| |-
I don't know what the squiggly lines...
Complcated Chemistry Reaction - impossible??
My notes say:
Step 1 is a 221 reaction. If peroxides are used in your version, then the anti-Markovnikov bromide is formed. If your version had only HBr, the the Markovnikov bromide is formeed.
Step 2 creates organolithium or Grignard...
My brain has been shocked by this problem dealing with charges and Coulombs law :(
This is what I did...
F = k*q1*q2/r^2
F = [ (8.99 * 10^9)(4.9 * 10-9)(6.0 * 10^-9) ] / (0.295)^2
F = 0.000000264 / 0.087025
F = 0.0000003034
F = 3.034 * 10^-7 N
F = k*q1*q3/r^2
F = [ (8.99 *...
Ok before we get to number 3, I need to show you what I did for number 2 because this is kind of a two-part problem:
PEinitial + KEinitial = PEfinal + KEfinal
mgy + (1/2)mvi2 = (1/2)mvf2
gy + (1/2)vi2 = (1/2)vf2
(9.81)(10) + (1/2)(102) = vf2/2
98.1 + 50 = vf2/2
148.1 = vf2/2
2(148.1) = vf2...
Help with Kinetic Energy concept of two masses that move the same distance!!
I don't understand why the answer to this is B :(
Because KE = (1/2)mv2, if they move the same distance and have DIFFERENT masses, the kinetic energies would be different no?
Ok so I tried making myself a free-body diagram but I reached a dead end..
Step 1) fkinetic = μkn
fkinetic = μk(251)
fkinetic / 251 = μk
n = (m)(g) = 251 N
ƩFx = m(-a) since it's moving the left or ƩFx = 0 (since it's moving at CONSTANT velocity)
ƩFy = ma...
So I'm given...
In the y-direction
vo = 0 m/s
vf = 7.5 m/s (is the speed of the ball thrown straight up)
g = -9.81 m/s2 (when it falls back down)
yo = 0 m
yf = 1.5 m (at this height above the ground, the bat connects with the ball)
t = ?
I tried doing this...
yf = yo + vyot +...
This is what I did:
Ʃτ = F2r2 + F1r1 = 0
(195)(7) + F1(0.7) = 0
F1(0.7) = -(195)(7)
F1 = -1365/0.7
F1 = -1950 N
F1 = 1950 N
Is that answer right?
This is what I did:
Since this is a massless rod and the location of the axis is through the end, I = ML2
Period for pendulum is T = 2π√(L/g)
When a pendulum is in an elevator and it goes up
T = 2π√(L/9.8+a)
T = T0
Elevator moves upward with constant acceleration a = 3g
T = 2π√(L/9.8+3g)
So I have to solve for T0
T0 = 2π√(L/9.8+a) = 2π√(L/9.8+3g)
T0 = (√(L/9.8+a))2...
This is what I tried doing, but I ended up getting an answer that isn't listed above
1. frequency = speed/wavelength
2. On Earth
480 Hz = (343 m/s)/wavelength
wavelength = 343 / 480
wavelength = 0.714 is the wavelength for the Coke bottle
3. On Earth 2
Since they already gave me...
I tried using Frsin θ
(270.756)(46 cm)sin (68) but I got 11547.86
And got it wrong...
And then I tried doing.
101.426982807+251.040591727 = 352.4 N*m but I got it wrong.
^ I don't remember how I did that but it was saved in my notes.
I need to get a 100 on this last Physics lab assignment, but I can't get this "rod"
Help would be appreciated
(a) L1 = (65 cm)/2 = 32.5 cm
(b) [(149 kg)(1) + (149 kg)(65 cm) + (149 kg)(65 cm + 32.5 cm)] / (3)(149 kg)
= (149 + 9685 + 14527.5) / (447)