Hmm interesting. I've got it now. The electric potential inside the shell is the sum of the electric potential on the outer edge and the inner edge.
This yields: V=k\frac{3Q}{4r_1}
Ok, but I'm still confused on the next question. I would think the electric potential inside the cavity would...
Yes, I know that
vec(E)=-vec(\nabla V)
I also know that
E=-\frac{dV}{ds} when ds||E
If I use the second equation I set E equal to zero and you have v=0 which is wrong. The first one I'm not even sure how to use since I have magnitudes of vectors not vectors.
Homework Statement
A hollow spherical conductor, carrying a net charge +Q, has inner radius r1 and outer r2=2r1 radius (see the figure ). At the center of the sphere is a point charge +Q/2.
A.Write the electric field strength E in all three regions as a function of r: for r>r2,r1<r<r2...
Homework Statement
An electron is separated from a potassium nucleus (charge 19e) by a distance of 5.2 X 10-10m. what is the electric force between these particles? (e = 1.60 X 10-19C, Kc= 8.99 X 109 N*m2/C2)
Homework Equations
Felectric= Kc[(q1)(q2)/r2]
The Attempt at a Solution...
I'm sorry but I don't know how you would combine these equations. I have tried to combine them but I come up with an answer that you wouldn't be able to solve for the v^2 and dosent seam logical.
K.E=(1/2)(m)(v^2)
P.E.= mgh
P.E/(G)(H)=m
K.E=(1/2)[P.E/(G)(H)](v^2)...
Yeah, your right.
I meant to put K.E.= (1/2)(m)(v^2)
I still don't understand what I'm suppose to do. Both equations require mass to solve for the potential or kinetic energy. Does mass matter in this problem because I don't think I can solve for the mass of the cannonball?
Homework Statement
A cannon shoots straight up into the air a cannonball which reaches a maximum height of 600m. What was the initial velocity of the cannonball when it was fired from the cannon. (Note: this problem contains all the information necessary to be solved.)
use g=10m/s^2...
Thanks,
So, if I correct my units I would have:
P.E.= mgh
P.E.=(2kg)(10m/s^2)(500m)
P.E.= 10000 joules
P.E. elastic= (1/2)(k)(x^2)
k= P.E elastic/ (1/2)(x^2)
k= 10000/ (1/2)(1)
k=20000 N/m ?
Is this correct?
Homework Statement
A spring is compressed a distance of 1m and a 2 kg rock is shot straight up with the spring. The rock attains a maximum height of 500m. What is the force constant k of the spring?
Use g=10m/s^2
Homework Equations
P.E.= mgh
P.E. elastic= (1/2)(k)(x^2)
The Attempt...