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  1. J

    Electron Velocity

    W=q(Delta V) = Change in kinetic energy, which is (-1.6*10^-19 C)(3000V) = -4.8*10^-16 N*m -4.8*10^-16 N*m = .5*(9.109*10^-31 kg)*(v^2) Since a newton is kg*m/s^2, the kg's cancel and im left with m^2/s^2 Sorry for the confusion.
  2. J

    Electron Velocity

    -4.8*10^-16 = .5*(9.109*10^-31)*(v^2) So v = 3.246 * 10^7 m/s?
  3. J

    Electron Velocity

    I need to find the force. Once I find that everything else isn't difficult. Part I) Find the speed of the electron: v=F/(eB) W=q(Delta V) = F*d, where W is -4.8*10^-16 N*m Part II) Find the distance between the been entering and exiting the field. r=mv/(eB) where r is the radius so...
  4. J

    Electron Velocity

    Homework Statement An electron gun (applied voltage of 3000 volts) is emitting electrons. THe electrons enter a region of constant magnetic field (B=.025 Tesla.) The magnetic field is perpendicular to the velocity of the beam. Homework Equations W=Q(Delta V) = F*d V=F/eB The...
  5. J

    Expansion of Solids due to increases in Temperature

    I was given a question about a certain material. The idea was that when it was heated from zero degrees C to 200 degrees C, it would be 10.06 mm from its original length of 10. Doing it in reverse order, length of 10.06 mm from 200 C to 0 C gave me an answer of 9.99964, which is less than the...
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