The change in entropy for a reversible process is
DS = int (dQrev/T)
You should be able to calculate this if you know the equation of state for a perfect gas
Something else you need to consider: To derive the expression for v you used the result
vXB = - E
then I guess you took the cross product with B giving...
No problem about the vector notation.
The reason I wondered if there was more to the question because, in general, dv/dt wouldn't be zero.
Look up "velocity selector", for example https://en.wikipedia.org/wiki/Wien_filter (must admit I learned something as well, I never realised that velocity...
I think you first have to realise that you are dealing with vector quantities.
With just a magnetic field of strength B you have the force acting on a charge q moving with velocity v is mdv/dt = q vXB (where vectors are bold face).
In this situation if you assume that the charge moves...
I think you have made a mistake in some of your +ve/-ve signs and think that your approach would eventually give y = y.
The best way to go about this is to write cosx =(exp(ix) + exp(-ix))/2 (Euler's formula) and then you have to solve a differential equation of the form
dy/dx = exp(mx) where...
This is a request about the second order differential equation
y'' + (k^2 + f(r))y(r) = 0 (1)
where k is a (real) constant and f(r) is a real valued function of r that has some constraints regarding integratability.
According to...
I belierve there is a pd.
One reply suggested no pd because no current: This is wrong because (as pointed out)the resistance is infinite. So, you can have a pd between points but no current.
The terms met with in electricity have some historical bias. Voltage appears to come from the name of the scientist Alessandro Giuseppe Antonio Anastasio Volta who was one of the first people to investigate electric circuits (http://en.wikipedia.org/wiki/Alessandro_Volta)
One way to introduce...
Mass isn't invariant: It is the total mass+energy that is conserved.
As well, I'm not sure if you're aware of the well known formula from special relativity that relates the mass of a particle to its speed v: m = m0/sqrt( 1 - v^2/c^2)?
You may consider using the following:
gradXA = B
then use Stoke's theorem to write surface int(gradXA.dS) = line int (A.dl), with the closed curve chosen suitably.
This gives line int(A.dl) = int(B.ds).
The surface integral is straight forward...
You dont have a wave equation there, you have solutions to a wave equation.
As well, since cos(-z) = cos(z), i.e. cos is an even function you can write the cos solution as A cos (ωt - kx) if you wish.
The general solution to the wave equation is
Acos(wt - kx) + Bsin(wt -kx)
where A and B...
According to Pierret ("Advanced Semiconductor Fundamentals", Prentice Hall 2003, see pp 82-83) the manner that the band gap for a large number of semiconductors varies with T can be modelled by the empirical relationship
Eg(T) = Eg(0) - alpha*T^2/(T + beta)
where alpha...
The band (or energy) gap, Eg, for silicon is taken from experiment and is about 1.1-1.2 eV and is known to within 5%. It only has a relatively weak dependence upon temperature.
According to Aschrcoft and Mermin (Solid State Physics, Saunders Coolege Publishing, ):
Eg (0K) = 1.17 eV, Eg(300K)...
A book I've found useful is by Paul Harrison, "Computational Methods in Physics, Chemistry and Biology: An Introduction".
I liked it for the following reasons:
the level was reasonable, the style of the text and besides the code (C language) being available the author presented the psuedo...
Not sure when this question was posed. Even if it were sometime ago perhaps you may find my comments useful?
With regards Fig 7.53 (b). For times t < 0 when the switch is closed, the inductor acts like a piece of wire (since the current is constant so di/dt = 0 there is no emf induced, VL = L...
Can any one recommend any books that cover k.p theory so that a beginner may be able to (eg) get a realistic programme running? Perhaps aimed at the beginning PhD stage (so will have a good background in quantum mechanics)? I find journal articles difficult to follow, and have found no...