Chemistry- two point Arrhenius Equation (miscalculation??)
At 25 degrees celsius, the first-order rate constant for a reaction is 2.0 x 10^3 s^-1. The activation energy is 15.0 kJ/mol. what is the value of the rate constant at 75 degrees celsius.
T1= 298.15 K
A solution is made by dissolving 250.0 g of solid potassium chromate in 1.00 kg of water. What will be the freezing point of the new solution?
molal freezing point-depression constant of water = 1.86 degrees Celsius/molality
molality = mol/kg
Ok ok, so since it says 50 percent by mass HNO3 I assumed that it was part of a 100 percent solution. Meaning 100 grams. So I did the whole process again with the new calculations and got 63.0 mL.
Here is my work:
(50 g solution)(1 mL/2.00 g)(0.001 L/1 mL) = 0.05 L
(50 g HNO3)(1 mol...
How many mL of 50.0% by mass HNO3 solution, with a density of 2.00 g/mL is required to make a 500 mL of a 2.00 M HNO3?
initial Molarity X initial Volume = final Molarity X final Volume
The Attempt at a Solution
(50 g HNO3)(1 mL/2.00 g)(0.001 L/1 mL)...
I have recently just started studying chemistry for my Junior year in High School. So you could say that I am a newbie at this. :smile:
I have small knowledge on the relationship between Intermolecular Forces and Physical changes. (Example: Boiling Point.)
So if the IMF of a...