is that mean 2 orbitals with one occupied by 2 electrons and other with electron occupied singly,
and 2 orbitals both single occupied.
The repulsion between the latter one is greater than the former one?
so now the new configuration is
cu2+ has 3 unpaired 3d electrons whereas Cu+ has 2 unpaired electrons, in theory the unpaired electrons in Cu2+ will repelled from the inner electrons and thus more unstable?
Explain why copper(II) is the more common oxidation state than copper (I) by giving the electronic configurations of the ions involved.
The Attempt at a Solution
i've considered about the configurations of Cu+ and Cu2+ but the result seems to contradict the fact...