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    Finding the Electric Field of a Parallel Plate Capacitor

    Of course -_- . Thanks! Silly mistake. For anyone else who wants to use this thread: My mistake was writing t=x/cos(45) instead of t=x/(cos(45)*Vo) The end formula would then be: E = (m* Vo^2)/(q*x)
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    Finding the Electric Field of a Parallel Plate Capacitor

    Homework Statement An electron is launched at a 45∘ angle and a speed of Vo = 5.0×10^6 m/s from the positive plate of the parallel-plate capacitor towards the negative plate. The electron lands 4.0 cm away. Homework Equations F = ma = qE v = d/t s = vt -(1/2)at^2 x = 0.04 m The Attempt...
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    Finding the Electric Field at the Midpoint of two rings

    Homework Statement Hello, Two 10-cm-diameter charged rings face each other, 20 cm apart. The left ring is charged to -22 nC and the right ring is charged to +22 nC . What is the magnitude of the electric field E⃗ at the midpoint between the two rings? Homework Equations [/B] E = Kq/r^2 K =...
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    Calculating the electric flux

    Homework Statement Hello, A 3.60cm x 4.50cm rectangle lies in the xy-plane. What is the electric flux through the rectangle if E=(80.0i + 50k) N/C ? Homework Equations Φ = E * A =EAcos(θ) The Attempt at a Solution My attempt: First convert the rectangle units from cm to m. 4.50cm =...
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    Calculating the Electric FLux

    Thank you! I am new to using physics forums. I'll post it to the homework forum.
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    Calculating the Electric FLux

    Hello, The problem: A 3.60cm x 4.50cm rectangle lies in the xy-plane. What is the electric flux through the rectangle if E=(80.0i + 50k) N/C ? My attempt: First convert the rectangle units from cm to m. 4.50cm = 0.045m 3.60cm = 0.036m Find the area of the rectangle. A = 0.036m x 0.045m =...
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