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2. ### Verticle launch velocity given only time.

ok...Thank you for the help I appreciate it.
3. ### Verticle launch velocity given only time.

and 1.37s is the time it took to go up and down
4. ### Verticle launch velocity given only time.

well 1.37s is all that I was given in which I am suppose to use to find out the Launch velocity of the cork.
5. ### Verticle launch velocity given only time.

well I was assuming that the total distance would be 9.2m to travel the full parabola or 4.6m to get to maximum height I was getting there through my own weird means. I tend to take unorthodox methods to get to answers. I just want to know if it took a cork 1.37s to go up and down if the...
6. ### Verticle launch velocity given only time.

jeeze i should re-read what I post. The time i presented is the time the cork took to travel vertically up and down and I am looking for the launch velocity of the cork. I used d=1/2at^2 equation so that I could find the full distance that it traveled I just derived it from d=1/2at^2+vt if that...
7. ### Verticle launch velocity given only time.

Homework Statement you are given the time it takes for a cork to be launched up vertically which is 1.37s Homework Equations d=1/2at^2+vt The Attempt at a Solution d=1/2(9.8)(1.37)^2 d=9.2m Because I wanted the height of the parabola I devided both the time and the distance by 2...