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  1. J

    Velocity of a proton question

    So would the correct answer be... 120 * 1.6 x 10-19 = 1.92 x 10 -17 sqrt(2*1.92 x 10 -17/1.7 x 10-27) = v = 1.5 x 105 ms-1
  2. J

    Velocity of a proton question

    By definition, it is equal to the amount of kinetic energy gained by a single unbound electron when it accelerates through an electrostatic potential difference of one volt. (from Wiki) Oh, my tutor told me to divide... Is it because 1 Volt = 1 Joule/1 Coulomb There for Joules = V * C...
  3. J

    Velocity of a proton question

    Homework Statement Calculate the veolcity of a proton of energy 0.12 keV proton mass = 1.7 x 10^-27 Homework Equations The Attempt at a Solution I thought... 0.12 keV = 120 eV 120/1.60 x 10^-19 = 7.5 x 10^20 J E = 0.5mv^2 sqrt(2E/m) = v but I'm getting something to x 10^23 so its...
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